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In a parallel RLC circuit, if the lower cut-off frequency is 2400 Hz and the upper cut-off frequency is 2800 Hz, what is the bandwidth?
  • a)
    120 Hz
  • b)
    2400 Hz
  • c)
    400 Hz
  • d)
    5200 Hz
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In a parallel RLC circuit, if the lower cut-off frequency is 2400 Hz a...
Bandwidth = f- fL
(=2800 - 2400)
(=400 Hz)
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Most Upvoted Answer
In a parallel RLC circuit, if the lower cut-off frequency is 2400 Hz a...
Explanation:
A parallel RLC circuit has three elements - resistor, inductor and capacitor connected in parallel. The bandwidth of a parallel RLC circuit is defined as the difference between the upper and lower cut-off frequencies.


Formula:
Bandwidth = upper cut-off frequency - lower cut-off frequency


Given:
Lower cut-off frequency = 2400 Hz

Upper cut-off frequency = 2800 Hz


Solution:
Substituting the given values in the formula, we get:

Bandwidth = 2800 Hz - 2400 Hz = 400 Hz


Therefore, the bandwidth of the parallel RLC circuit is 400 Hz. Hence, option (c) is the correct answer.
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Community Answer
In a parallel RLC circuit, if the lower cut-off frequency is 2400 Hz a...
Bandwidth = f- fL
(=2800 - 2400)
(=400 Hz)
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In a parallel RLC circuit, if the lower cut-off frequency is 2400 Hz and the upper cut-off frequency is 2800 Hz, what is the bandwidth?a)120 Hzb)2400 Hzc)400 Hzd)5200 HzCorrect answer is option 'C'. Can you explain this answer?
Question Description
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