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A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld is
- a)142 MPa
- b)166 MPa
- c)119 MPa
- d)138MPa
Correct answer is option 'C'. Can you explain this answer?
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A flat plate is welded to a gusset plate by a fillet weld of size 10 ...
Factored load-carrying capacity of the weld,
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P = permissible shear stress in the weld(fy) × effective area of the weld the effective area of the weld = effective length of the weld(Leff)× throat thickness(Tt)
Therefore, P = fy × Leff × Tt
since, the angle between the fusion faces is 85°, Tt = 0.7 × size of the weld
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A flat plate is welded to a gusset plate by a fillet weld of size 10 ...
Given data:
- Size of the fillet weld: 10 mm
- Angle between the fusion faces: 85°
- Effective length of the weld: 300 mm
- Axial factored load acting on the plate: 250 kN
To find: Average shear stress produced in the weld
We can calculate the average shear stress using the formula:
Average shear stress = Force / Area
Finding the force:
The axial factored load acting on the plate is 250 kN. However, since we are interested in shear stress, we need to consider only the component of the force that is perpendicular to the weld. This component can be calculated using the formula:
Force perpendicular to weld = Axial force x sin(angle between fusion faces)
Force perpendicular to weld = 250 kN x sin(85°)
Force perpendicular to weld = 250 kN x 0.9962
Force perpendicular to weld ≈ 249.05 kN
Finding the area:
To calculate the area, we need to determine the effective throat thickness of the weld. This can be calculated using the formula:
Effective throat thickness = Size of fillet weld x sin(angle between fusion faces)
Effective throat thickness = 10 mm x sin(85°)
Effective throat thickness = 10 mm x 0.9962
Effective throat thickness ≈ 9.96 mm
The area of the weld can be calculated as follows:
Area = Effective throat thickness x Length of the weld
Area = 9.96 mm x 300 mm
Area = 2988 mm²
Converting the area from mm² to m²:
Area = 2988 mm² x (1 m / 1000 mm)²
Area = 2.988 x 10⁻³ m²
Finally, we can calculate the average shear stress:
Average shear stress = Force / Area
Average shear stress = 249.05 kN / 2.988 x 10⁻³ m²
Average shear stress ≈ 83.33 MPa
Therefore, the average shear stress produced in the weld is approximately 83.33 MPa.
- Size of the fillet weld: 10 mm
- Angle between the fusion faces: 85°
- Effective length of the weld: 300 mm
- Axial factored load acting on the plate: 250 kN
To find: Average shear stress produced in the weld
We can calculate the average shear stress using the formula:
Average shear stress = Force / Area
Finding the force:
The axial factored load acting on the plate is 250 kN. However, since we are interested in shear stress, we need to consider only the component of the force that is perpendicular to the weld. This component can be calculated using the formula:
Force perpendicular to weld = Axial force x sin(angle between fusion faces)
Force perpendicular to weld = 250 kN x sin(85°)
Force perpendicular to weld = 250 kN x 0.9962
Force perpendicular to weld ≈ 249.05 kN
Finding the area:
To calculate the area, we need to determine the effective throat thickness of the weld. This can be calculated using the formula:
Effective throat thickness = Size of fillet weld x sin(angle between fusion faces)
Effective throat thickness = 10 mm x sin(85°)
Effective throat thickness = 10 mm x 0.9962
Effective throat thickness ≈ 9.96 mm
The area of the weld can be calculated as follows:
Area = Effective throat thickness x Length of the weld
Area = 9.96 mm x 300 mm
Area = 2988 mm²
Converting the area from mm² to m²:
Area = 2988 mm² x (1 m / 1000 mm)²
Area = 2.988 x 10⁻³ m²
Finally, we can calculate the average shear stress:
Average shear stress = Force / Area
Average shear stress = 249.05 kN / 2.988 x 10⁻³ m²
Average shear stress ≈ 83.33 MPa
Therefore, the average shear stress produced in the weld is approximately 83.33 MPa.
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A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer?
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A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer?.
A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A flat plate is welded to a gusset plate by a fillet weld of size 10 mm. The angle between the fusion faces and the effective length of the weld is 85° and 300 mm respectively. If the axial factored load acting on the plate is 250 kN, then the average shear stress produced in the weld isa)142 MPab)166 MPac)119 MPad)138MPaCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
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