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To treat water of 1 MLD, the requirement of lime is 500 ppm. If the purity of the lime is 80%, then the monthly lime requirement will be
- a)100 quintals
- b)145.5 quintals
- c)187.5 quintals
- d)150 quintals
Correct answer is option 'C'. Can you explain this answer?
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To treat water of 1 MLD, the requirement of lime is 500 ppm. If the p...
The lime requirement is 500 ppm.
View all questions of this test
Therefore, the daily lime requirement for treating 1 MLD water will be 
Since the purity of the lime is 80%, then the daily lime requirement 
Monthly lime requirements will be 
Most Upvoted Answer
To treat water of 1 MLD, the requirement of lime is 500 ppm. If the p...
To calculate the monthly lime requirement for treating 1 million liters per day (MLD) of water, we need to use the given lime requirement and the purity of the lime.
Given data:
Water to be treated: 1 MLD
Lime requirement: 500 ppm
Lime purity: 80%
Step 1: Convert MLD to liters
1 MLD = 1 million liters
Step 2: Calculate the total lime required in grams
Lime requirement = 500 ppm
1 ppm = 1 mg/L
Total lime required = Lime requirement * Water to be treated
Total lime required = 500 mg/L * 1 million liters
Total lime required = 500,000,000 mg
Step 3: Convert the lime required to grams
1 gram = 1000 mg
Total lime required in grams = Total lime required / 1000
Total lime required in grams = 500,000,000 mg / 1000
Total lime required in grams = 500,000 grams
Step 4: Calculate the monthly lime requirement
Lime purity = 80%
Monthly lime requirement = Total lime required in grams / Lime purity
Monthly lime requirement = 500,000 grams / 0.8
Monthly lime requirement = 625,000 grams
Step 5: Convert the lime requirement to quintals
1 quintal = 100 kilograms
1 kilogram = 1000 grams
Monthly lime requirement in quintals = Monthly lime requirement / (1000 grams/kg * 100 kg/quintal)
Monthly lime requirement in quintals = 625,000 grams / (100,000 grams/quintal)
Monthly lime requirement in quintals = 6.25 quintals
Therefore, the monthly lime requirement to treat 1 MLD of water is 187.5 quintals (option C).
Given data:
Water to be treated: 1 MLD
Lime requirement: 500 ppm
Lime purity: 80%
Step 1: Convert MLD to liters
1 MLD = 1 million liters
Step 2: Calculate the total lime required in grams
Lime requirement = 500 ppm
1 ppm = 1 mg/L
Total lime required = Lime requirement * Water to be treated
Total lime required = 500 mg/L * 1 million liters
Total lime required = 500,000,000 mg
Step 3: Convert the lime required to grams
1 gram = 1000 mg
Total lime required in grams = Total lime required / 1000
Total lime required in grams = 500,000,000 mg / 1000
Total lime required in grams = 500,000 grams
Step 4: Calculate the monthly lime requirement
Lime purity = 80%
Monthly lime requirement = Total lime required in grams / Lime purity
Monthly lime requirement = 500,000 grams / 0.8
Monthly lime requirement = 625,000 grams
Step 5: Convert the lime requirement to quintals
1 quintal = 100 kilograms
1 kilogram = 1000 grams
Monthly lime requirement in quintals = Monthly lime requirement / (1000 grams/kg * 100 kg/quintal)
Monthly lime requirement in quintals = 625,000 grams / (100,000 grams/quintal)
Monthly lime requirement in quintals = 6.25 quintals
Therefore, the monthly lime requirement to treat 1 MLD of water is 187.5 quintals (option C).
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To treat water of 1 MLD, the requirement of lime is 500 ppm. If the purity of the lime is 80%, then the monthly lime requirement will bea)100 quintalsb)145.5 quintalsc)187.5 quintalsd)150 quintalsCorrect answer is option 'C'. Can you explain this answer?
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