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When a sinusoidal voltage is applied across the R-L parallel circuit so that (R=XL) the phase angle will be-
- a)(45°) lag
- b)(45°) leading
- c)(90°) lag
- d)(90°) leading
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
When a sinusoidal voltage is applied across the R-L parallel circuit ...
For the R - L series circuit, the phase angle
So it lags 45°
Hence, the correct option is (A)
Most Upvoted Answer
When a sinusoidal voltage is applied across the R-L parallel circuit ...
Explanation:
When the resistance R in an R-L parallel circuit is equal to the inductive reactance XL, the circuit is said to be at resonance. At resonance, the circuit impedance is purely resistive, and the phase angle between the voltage and current is either 0° or 180°.
In this case, the phase angle is given by the formula:
φ = tan⁻¹(XL/R)
Since R = XL, the phase angle becomes:
φ = tan⁻¹(1) = 45°
Therefore, the phase angle is 45° lagging.
Summary:
At resonance, the phase angle between the voltage and current in an R-L parallel circuit where R = XL is 45° lagging.
When the resistance R in an R-L parallel circuit is equal to the inductive reactance XL, the circuit is said to be at resonance. At resonance, the circuit impedance is purely resistive, and the phase angle between the voltage and current is either 0° or 180°.
In this case, the phase angle is given by the formula:
φ = tan⁻¹(XL/R)
Since R = XL, the phase angle becomes:
φ = tan⁻¹(1) = 45°
Therefore, the phase angle is 45° lagging.
Summary:
At resonance, the phase angle between the voltage and current in an R-L parallel circuit where R = XL is 45° lagging.
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Community Answer
When a sinusoidal voltage is applied across the R-L parallel circuit ...
For the R - L series circuit, the phase angle
So it lags 45°
Hence, the correct option is (A)
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