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A 200 W, 200 V bulb and a 100 W, 200 V bulb are connected in series and the voltage of 400 V is applied across the series connected bulbs, Under this condition
- a)100 W bulb will be brighter than 200 W bulb
- b)200 W bulb will be brighter than 100 W bulb
- c)Both the bulbs will have equal brightness
- d)Both the bulbs will be darker than when they are connected across rated voltage
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A 200 W, 200 V bulb and a 100 W, 200 V bulb are connected in series a...
For 200 W, 200 V,
For 100 W, 200 W,
current
For Bulb (1), power
For bulb (2), power
Hence 100W bulbs will be brighter than 2000 W bulbs.
Most Upvoted Answer
A 200 W, 200 V bulb and a 100 W, 200 V bulb are connected in series a...
Explanation:
When bulbs are connected in series, the same current flows through both bulbs. According to Ohm's law, the current flowing through a resistor is directly proportional to the voltage across it and inversely proportional to its resistance.
In this case, both bulbs have the same voltage across them (200 V) but different power ratings. The power of a bulb is given by the equation P = V^2/R, where P is power, V is voltage, and R is resistance.
Let's calculate the resistance of each bulb using the power and voltage values given:
For the 200 W bulb:
P = 200 W
V = 200 V
Using the power equation:
200 = 200^2/R
R = (200^2)/200
R = 200 ohms
For the 100 W bulb:
P = 100 W
V = 200 V
Using the power equation:
100 = 200^2/R
R = (200^2)/100
R = 400 ohms
Comparing the brightness:
The brightness of a bulb is directly proportional to the power dissipated in it. Therefore, the bulb with a higher power rating will be brighter.
In this case, the 200 W bulb has a higher power rating than the 100 W bulb. Since both bulbs have the same voltage across them, the bulb with higher power will dissipate more power and hence will be brighter.
Therefore, the correct answer is option 'A': The 100 W bulb will be brighter than the 200 W bulb when connected in series.
When bulbs are connected in series, the same current flows through both bulbs. According to Ohm's law, the current flowing through a resistor is directly proportional to the voltage across it and inversely proportional to its resistance.
In this case, both bulbs have the same voltage across them (200 V) but different power ratings. The power of a bulb is given by the equation P = V^2/R, where P is power, V is voltage, and R is resistance.
Let's calculate the resistance of each bulb using the power and voltage values given:
For the 200 W bulb:
P = 200 W
V = 200 V
Using the power equation:
200 = 200^2/R
R = (200^2)/200
R = 200 ohms
For the 100 W bulb:
P = 100 W
V = 200 V
Using the power equation:
100 = 200^2/R
R = (200^2)/100
R = 400 ohms
Comparing the brightness:
The brightness of a bulb is directly proportional to the power dissipated in it. Therefore, the bulb with a higher power rating will be brighter.
In this case, the 200 W bulb has a higher power rating than the 100 W bulb. Since both bulbs have the same voltage across them, the bulb with higher power will dissipate more power and hence will be brighter.
Therefore, the correct answer is option 'A': The 100 W bulb will be brighter than the 200 W bulb when connected in series.
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A 200 W, 200 V bulb and a 100 W, 200 V bulb are connected in series and the voltage of 400 V is applied across the series connected bulbs, Under this conditiona)100 W bulb will be brighter than 200 W bulbb)200 W bulb will be brighter than 100 W bulbc)Both the bulbs will have equal brightnessd)Both the bulbs will be darker than when they are connected across rated voltageCorrect answer is option 'A'. Can you explain this answer?
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ample number of questions to practice A 200 W, 200 V bulb and a 100 W, 200 V bulb are connected in series and the voltage of 400 V is applied across the series connected bulbs, Under this conditiona)100 W bulb will be brighter than 200 W bulbb)200 W bulb will be brighter than 100 W bulbc)Both the bulbs will have equal brightnessd)Both the bulbs will be darker than when they are connected across rated voltageCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice SSC tests.
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