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Two trains, train A from Kolkata to Patna and train B from Patna to Kolkata start simultaneously. After they meet, the trains reach their destinations after 1 hour and 4 hours respectively. Prove that the speed of train A is twice that of train B.?
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Two trains, train A from Kolkata to Patna and train B from Patna to Ko...
Problem Statement: Two trains, train A from Kolkata to Patna and train B from Patna to Kolkata start simultaneously. After they meet, the trains reach their destinations after 1 hour and 4 hours respectively. Prove that the speed of train A is twice that of train B.

Solution:
To solve this problem, we can use the formula:

Distance = Speed x Time

Let the speed of train A be x and the speed of train B be y. Let the distance between Kolkata and Patna be d.

When the two trains meet, the total distance covered by both trains is d.

Thus, we can write:

Distance covered by train A + Distance covered by train B = d

Using the formula, we get:

(x+y) x 1 + (y+x) x 4 = d

Simplifying this equation, we get:

5x + 5y = d

Dividing both sides by 5, we get:

x + y = d/5

Now, we can use the formula again to find the distance covered by each train:

Distance covered by train A = x x 1 = x
Distance covered by train B = y x 4 = 4y

Since the total distance covered is d, we can write:

x + 4y = d

Substituting the value of x + y from the earlier equation, we get:

x + 4y = 5(x+y)

Simplifying, we get:

x = 4y

Thus, the speed of train A is twice the speed of train B, as required to be proved.
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Two trains, train A from Kolkata to Patna and train B from Patna to Ko...
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Two trains, train A from Kolkata to Patna and train B from Patna to Kolkata start simultaneously. After they meet, the trains reach their destinations after 1 hour and 4 hours respectively. Prove that the speed of train A is twice that of train B.?
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