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The full load copper-loss in a transformer is 1600W. At half load, the copper-loss will be
  • a)
    400 W
  • b)
    200 W
  • c)
    150 W
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The full load copper-loss in a transformer is 1600W. At half load, th...
The copper losses of the transformer at x times the full load is proportional to x2 times the losses at full load.
Hence at half the full load, the copper losses will be (0.5)2×1600 = 400 Watts.
Hence, the correct option is (A)
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Most Upvoted Answer
The full load copper-loss in a transformer is 1600W. At half load, th...

Explanation:

Given:
Full load copper-loss = 1600W

Calculating Half Load Copper-loss:
At half load, the copper-loss is proportional to the square of the current. Since power loss is directly proportional to the square of the current, at half load, the copper-loss will be one-fourth of the full load copper-loss.

Therefore, half load copper-loss = 1600W / 4 = 400W

So, the correct answer is option A which is 400W.
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The full load copper-loss in a transformer is 1600W. At half load, the copper-loss will bea)400 Wb)200 Wc)150 Wd)None of theseCorrect answer is option 'A'. Can you explain this answer?
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