NEET Exam > NEET Questions > A particle is moving at a constant speed in a...
Start Learning for Free
A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.?
Verified Answer
A particle is moving at a constant speed in a circular trajectory cent...
The acceleration of the particle is given by the formula a = v^2/r, where a is the acceleration, v is the velocity of the particle, and r is the radius of the circular trajectory. Since the velocity of the particle at the point (x=4m, y=0m) is -5.0 j m/s, and the radius of the circular trajectory is 4m, the acceleration of the particle is given by a = (-5.0 j m/s)^2 / 4m = (-25 j m^2/s^2)/4m = -6.25 j m/s^2. Therefore, the acceleration of the particle is -6.25 j m/s^2.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
A particle is moving at a constant speed in a circular trajectory cent...
Given information:
- The particle is moving at a constant speed in a circular trajectory centered at the origin of an xy-coordinate system.
- At one point (x=4m, y=0m), the particle has a velocity of -5.0 j m/s.
Understanding the problem:
We need to determine the acceleration of the particle at the given point. Since the particle is moving in a circular trajectory, it experiences centripetal acceleration towards the center of the circle.
Calculating centripetal acceleration:
The centripetal acceleration can be calculated using the formula:
a = v²/r
where a is the centripetal acceleration, v is the velocity of the particle, and r is the radius of the circular trajectory.
Identifying key values:
- The given velocity of the particle is -5.0 j m/s. Since the velocity is given in vector form, it has a magnitude of 5.0 m/s and is directed in the negative y-direction.
- The x-coordinate of the particle is 4m, which gives us the radius of the circular trajectory, r = 4m.
Calculating centripetal acceleration:
Using the formula above, we can calculate the centripetal acceleration as follows:
a = (5.0 m/s)² / 4m
a = 25 m²/s² / 4m
a = 6.25 m/s²
Therefore, the acceleration of the particle at the given point is 6.25 m/s². This acceleration is directed towards the center of the circular trajectory.
Explanation:
The centripetal acceleration is the acceleration experienced by an object moving in a circular path. It is always directed towards the center of the circle and its magnitude depends on the velocity of the object and the radius of the circle. In this case, the particle has a velocity of -5.0 j m/s, which means it is moving in the negative y-direction. The x-coordinate of the particle is 4m, which gives us the radius of the circular trajectory. By substituting these values into the formula for centripetal acceleration, we can calculate the acceleration as 6.25 m/s². This acceleration indicates that the particle is accelerating towards the center of the circular trajectory.
- The particle is moving at a constant speed in a circular trajectory centered at the origin of an xy-coordinate system.
- At one point (x=4m, y=0m), the particle has a velocity of -5.0 j m/s.
Understanding the problem:
We need to determine the acceleration of the particle at the given point. Since the particle is moving in a circular trajectory, it experiences centripetal acceleration towards the center of the circle.
Calculating centripetal acceleration:
The centripetal acceleration can be calculated using the formula:
a = v²/r
where a is the centripetal acceleration, v is the velocity of the particle, and r is the radius of the circular trajectory.
Identifying key values:
- The given velocity of the particle is -5.0 j m/s. Since the velocity is given in vector form, it has a magnitude of 5.0 m/s and is directed in the negative y-direction.
- The x-coordinate of the particle is 4m, which gives us the radius of the circular trajectory, r = 4m.
Calculating centripetal acceleration:
Using the formula above, we can calculate the centripetal acceleration as follows:
a = (5.0 m/s)² / 4m
a = 25 m²/s² / 4m
a = 6.25 m/s²
Therefore, the acceleration of the particle at the given point is 6.25 m/s². This acceleration is directed towards the center of the circular trajectory.
Explanation:
The centripetal acceleration is the acceleration experienced by an object moving in a circular path. It is always directed towards the center of the circle and its magnitude depends on the velocity of the object and the radius of the circle. In this case, the particle has a velocity of -5.0 j m/s, which means it is moving in the negative y-direction. The x-coordinate of the particle is 4m, which gives us the radius of the circular trajectory. By substituting these values into the formula for centripetal acceleration, we can calculate the acceleration as 6.25 m/s². This acceleration indicates that the particle is accelerating towards the center of the circular trajectory.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.?
Question Description
A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.?.
A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.?.
Solutions for A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? defined & explained in the simplest way possible. Besides giving the explanation of
A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.?, a detailed solution for A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? has been provided alongside types of A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? theory, EduRev gives you an
ample number of questions to practice A particle is moving at a constant speed in a circular trajectory centered at the origin of an xy co-ordinate system. at one point (x=4m, y=0m) the particle has a velocity -5.0 j m/s. determine acceleration of particle.? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup