Tolerances for a hole and shaft assembly having a nominal size of 40 mm are as follows :Determine the Maximum material Limit (MML) of the hole.a)39.94 mmb)40.06 mmc)40.02 mmd)39.92 mmCorrect answer is option 'C'. Can you explain this answer?

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Tolerances for a hole and shaft assembly having a nominal size of 40 mm are as follows :

Determine the Maximum material Limit (MML) of the hole.

a)
39.94 mm
b)
40.06 mm
c)
40.02 mm
d)
39.92 mm

Correct answer is option 'C'. Can you explain this answer?

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Tolerances for a hole and shaft assembly having a nominal size of 40 ...

The maximum material Limit (MML) in case of the hole is the lower limit of the hole.

Or the 'GO' condition,

Given dimension of hole =

base size of hole = 40 mm

upper limit of hole = 40 + 0.06 = 40.06 mm

lower limit of hole = 40 + 0.02 = 40.02 mm

So MML for hole = lower limit of hole

= 40 + 0.02 = 40.02;mm

and 'NO GO' condition or minimum material limit or the upper limit of hole = 40.06 mm

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Tolerances for a hole and shaft assembly having a nominal size of 40 mm are as follows :Determine the Maximum material Limit (MML) of the hole.a)39.94 mmb)40.06 mmc)40.02 mmd)39.92 mmCorrect answer is option 'C'. Can you explain this answer?

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Tolerances for a hole and shaft assembly having a nominal size of 40 mm are as follows :Determine the Maximum material Limit (MML) of the hole.a)39.94 mmb)40.06 mmc)40.02 mmd)39.92 mmCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about Tolerances for a hole and shaft assembly having a nominal size of 40 mm are as follows :Determine the Maximum material Limit (MML) of the hole.a)39.94 mmb)40.06 mmc)40.02 mmd)39.92 mmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Tolerances for a hole and shaft assembly having a nominal size of 40 mm are as follows :Determine the Maximum material Limit (MML) of the hole.a)39.94 mmb)40.06 mmc)40.02 mmd)39.92 mmCorrect answer is option 'C'. Can you explain this answer?.

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