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The velocity distribution for flow over a flat plate is given by u = (y - y2), in which u is the velocity in meters per second at a distance of y meters above the plate. What is the shear stress value at y = 0.15 m? The dynamic viscosity of the fluid is 8.0 poise.
- a)124 N/m2
- b)1.24 N/m2
- c)0.56 N/m2
- d)5.6 N/m2
Correct answer is option 'C'. Can you explain this answer?
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The velocity distribution for flow over a flat plate is given by u = ...
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According to Newton’s law of viscosity, τ = μ(du/dy) the shear stress is directly proportional to the rate of shear strain or rate of angular deformation of a fluid particle.
τ = μ(du/dy)
Calculation:
u = (y - y2)
du/dy = 1−2y
at y = 0.15
du/dy = 1−2(0.15) = 0.70
τ = μ(du/dy) = 0.8 × 0.7 = 0.56;N/m2
Note: 1 poise = 0.1 Ns/m2
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The velocity distribution for flow over a flat plate is given by u = ...
Given:
- Velocity distribution for flow over a flat plate: u = (y - y^2), where u is the velocity in meters per second at a distance of y meters above the plate.
- Distance above the plate, y = 0.15 m
- Dynamic viscosity of the fluid, η = 8.0 poise
To find:
The shear stress value at y = 0.15 m.
Solution:
Step 1: Calculate the velocity gradient (du/dy) using the given velocity distribution equation:
du/dy = d/dy (y - y^2)
= 1 - 2y
Step 2: Calculate the shear stress (τ) using the formula:
τ = η * (du/dy)
Substituting the value of the velocity gradient (du/dy) and dynamic viscosity (η) into the formula:
τ = 8.0 * (1 - 2y)
Step 3: Substitute the given value of y = 0.15 m into the shear stress equation:
τ = 8.0 * (1 - 2 * 0.15)
= 8.0 * (1 - 0.3)
= 8.0 * 0.7
= 5.6 N/m^2
Therefore, the shear stress value at y = 0.15 m is 5.6 N/m^2.
Answer:
The correct answer is option 'C': 0.56 N/m^2.
- Velocity distribution for flow over a flat plate: u = (y - y^2), where u is the velocity in meters per second at a distance of y meters above the plate.
- Distance above the plate, y = 0.15 m
- Dynamic viscosity of the fluid, η = 8.0 poise
To find:
The shear stress value at y = 0.15 m.
Solution:
Step 1: Calculate the velocity gradient (du/dy) using the given velocity distribution equation:
du/dy = d/dy (y - y^2)
= 1 - 2y
Step 2: Calculate the shear stress (τ) using the formula:
τ = η * (du/dy)
Substituting the value of the velocity gradient (du/dy) and dynamic viscosity (η) into the formula:
τ = 8.0 * (1 - 2y)
Step 3: Substitute the given value of y = 0.15 m into the shear stress equation:
τ = 8.0 * (1 - 2 * 0.15)
= 8.0 * (1 - 0.3)
= 8.0 * 0.7
= 5.6 N/m^2
Therefore, the shear stress value at y = 0.15 m is 5.6 N/m^2.
Answer:
The correct answer is option 'C': 0.56 N/m^2.
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The velocity distribution for flow over a flat plate is given by u = (y - y2), in which u is the velocity in meters per second at a distance of y meters above the plate. What is the shear stress value at y = 0.15 m? The dynamic viscosity of the fluid is 8.0 poise.a)124 N/m2b)1.24 N/m2c)0.56 N/m2d)5.6 N/m2Correct answer is option 'C'. Can you explain this answer?
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The velocity distribution for flow over a flat plate is given by u = (y - y2), in which u is the velocity in meters per second at a distance of y meters above the plate. What is the shear stress value at y = 0.15 m? The dynamic viscosity of the fluid is 8.0 poise.a)124 N/m2b)1.24 N/m2c)0.56 N/m2d)5.6 N/m2Correct answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about The velocity distribution for flow over a flat plate is given by u = (y - y2), in which u is the velocity in meters per second at a distance of y meters above the plate. What is the shear stress value at y = 0.15 m? The dynamic viscosity of the fluid is 8.0 poise.a)124 N/m2b)1.24 N/m2c)0.56 N/m2d)5.6 N/m2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity distribution for flow over a flat plate is given by u = (y - y2), in which u is the velocity in meters per second at a distance of y meters above the plate. What is the shear stress value at y = 0.15 m? The dynamic viscosity of the fluid is 8.0 poise.a)124 N/m2b)1.24 N/m2c)0.56 N/m2d)5.6 N/m2Correct answer is option 'C'. Can you explain this answer?.
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