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In an experiment for the determination of the shrinkage limit, the following observations are taken
(a) the volume of saturated soil = 9.95 ml
(b) mass of saturated soil = 17.5 ml
(c) the volume of dry soil after shrinkage = 5.60 ml
(d) mass of dry soil after shrinkage = 11.5 ml
compute the shrinkage limit and the specific gravity of soils
- a)0.4043,2.91
- b)0.4403,2.81
- c)0.4304,2.51
- d)0.4213,2.61
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
In an experiment for the determination of the shrinkage limit, the fo...
V1 = 9.95ml M1 = 17.5ml
V2 = 5.60ml Ms = 11.5ml
Ws = 0.4043 = 40.43%
The specific gravity of solids
G = 2.91
Hence the correct answer is option A.
Most Upvoted Answer
In an experiment for the determination of the shrinkage limit, the fo...
Calculation of Shrinkage Limit and Specific Gravity of Soil
Given data:
Volume of saturated soil (V1) = 9.95 ml
Mass of saturated soil (M1) = 17.5 g
Volume of dry soil after shrinkage (V2) = 5.60 ml
Mass of dry soil after shrinkage (M2) = 11.5 g
1. Calculation of Shrinkage Limit:
Shrinkage limit is the water content at which further reduction in water content does not cause any reduction in the volume of soil.
Shrinkage limit (SL) = [(V1 - V2)/V1] x 100
SL = [(9.95 - 5.60)/9.95] x 100
SL = 43.72%
2. Calculation of Specific Gravity:
Specific gravity is the ratio of the mass of a given volume of soil solids to the mass of an equal volume of water at a specified temperature (usually 4°C).
Specific gravity (G) = M2 / [(V1 - V2) x ρw]
where, ρw = density of water at 4°C = 1000 kg/m³
Converting ml to m³:
V1 = 9.95 / 1000 = 0.00995 m³
V2 = 5.60 / 1000 = 0.00560 m³
G = 11.5 / [(0.00995 - 0.00560) x 1000]
G = 2.91
Therefore, the shrinkage limit of the soil is 0.4043 and the specific gravity of the soil is 2.91. The correct answer is option A.
Given data:
Volume of saturated soil (V1) = 9.95 ml
Mass of saturated soil (M1) = 17.5 g
Volume of dry soil after shrinkage (V2) = 5.60 ml
Mass of dry soil after shrinkage (M2) = 11.5 g
1. Calculation of Shrinkage Limit:
Shrinkage limit is the water content at which further reduction in water content does not cause any reduction in the volume of soil.
Shrinkage limit (SL) = [(V1 - V2)/V1] x 100
SL = [(9.95 - 5.60)/9.95] x 100
SL = 43.72%
2. Calculation of Specific Gravity:
Specific gravity is the ratio of the mass of a given volume of soil solids to the mass of an equal volume of water at a specified temperature (usually 4°C).
Specific gravity (G) = M2 / [(V1 - V2) x ρw]
where, ρw = density of water at 4°C = 1000 kg/m³
Converting ml to m³:
V1 = 9.95 / 1000 = 0.00995 m³
V2 = 5.60 / 1000 = 0.00560 m³
G = 11.5 / [(0.00995 - 0.00560) x 1000]
G = 2.91
Therefore, the shrinkage limit of the soil is 0.4043 and the specific gravity of the soil is 2.91. The correct answer is option A.
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In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer?
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In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer?.
In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer?.
Solutions for In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for SSC.
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In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer?, a detailed solution for In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In an experiment for the determination of the shrinkage limit, the following observations are taken(a) the volume of saturated soil = 9.95 ml(b) mass of saturated soil = 17.5 ml(c) the volume of dry soil after shrinkage = 5.60 ml(d) mass of dry soil after shrinkage = 11.5 mlcompute the shrinkage limit and the specific gravity of soilsa)0.4043,2.91b)0.4403,2.81c)0.4304,2.51d)0.4213,2.61Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice SSC tests.
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