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What is the difference in pressure head, measured by a mercury-oil differential manometer for a 20 cm difference of mercury level? (Specific Gravity of oil = 0.8)
- a)2.72 m of oil
- b)2.52 m of oil
- c)3.40 m of oil
- d)2.00 m of oil
Correct answer is option 'C'. Can you explain this answer?
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What is the difference in pressure head, measured by a mercury-oil di...
A simple manometer to measure gauge pressure
hA = x + y; hB = x
hAsA = hBsB
⇒ 0.20 × 13.6 = hB × 0.8
⇒ hB = 3.4 m
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What is the difference in pressure head, measured by a mercury-oil di...
Difference in pressure head measured by a mercury-oil differential manometer for a 20 cm difference of mercury level.
To calculate the difference in pressure head measured by a mercury-oil differential manometer, we need to consider the specific gravity of the oil and the difference in the mercury level.
Given:
Difference in mercury level = 20 cm
Specific gravity of oil = 0.8
Step 1: Convert the mercury level difference to meters
Since the difference in the mercury level is given in centimeters, we need to convert it to meters.
20 cm = 20/100 = 0.2 meters
Step 2: Calculate the pressure difference between the two levels of mercury
The pressure difference between the two levels of mercury is given by the equation:
Pressure difference = (density of mercury) * (acceleration due to gravity) * (height difference)
The density of mercury is approximately 13,600 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².
Pressure difference = (13,600 kg/m³) * (9.8 m/s²) * (0.2 m)
= 2,672 Pascal
Step 3: Calculate the pressure head of the oil
The pressure head of the oil can be calculated using the equation:
Pressure head = (pressure difference) / (density of oil) / (acceleration due to gravity)
The density of oil is given by the specific gravity of oil multiplied by the density of water (1000 kg/m³).
Density of oil = (specific gravity of oil) * (density of water)
= 0.8 * 1000 kg/m³
= 800 kg/m³
Pressure head = (2,672 Pascal) / (800 kg/m³) / (9.8 m/s²)
≈ 0.340 meters
Therefore, the difference in pressure head measured by a mercury-oil differential manometer for a 20 cm difference of mercury level is approximately 0.340 meters of oil. So, the correct answer is option 'C'.
To calculate the difference in pressure head measured by a mercury-oil differential manometer, we need to consider the specific gravity of the oil and the difference in the mercury level.
Given:
Difference in mercury level = 20 cm
Specific gravity of oil = 0.8
Step 1: Convert the mercury level difference to meters
Since the difference in the mercury level is given in centimeters, we need to convert it to meters.
20 cm = 20/100 = 0.2 meters
Step 2: Calculate the pressure difference between the two levels of mercury
The pressure difference between the two levels of mercury is given by the equation:
Pressure difference = (density of mercury) * (acceleration due to gravity) * (height difference)
The density of mercury is approximately 13,600 kg/m³, and the acceleration due to gravity is approximately 9.8 m/s².
Pressure difference = (13,600 kg/m³) * (9.8 m/s²) * (0.2 m)
= 2,672 Pascal
Step 3: Calculate the pressure head of the oil
The pressure head of the oil can be calculated using the equation:
Pressure head = (pressure difference) / (density of oil) / (acceleration due to gravity)
The density of oil is given by the specific gravity of oil multiplied by the density of water (1000 kg/m³).
Density of oil = (specific gravity of oil) * (density of water)
= 0.8 * 1000 kg/m³
= 800 kg/m³
Pressure head = (2,672 Pascal) / (800 kg/m³) / (9.8 m/s²)
≈ 0.340 meters
Therefore, the difference in pressure head measured by a mercury-oil differential manometer for a 20 cm difference of mercury level is approximately 0.340 meters of oil. So, the correct answer is option 'C'.
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What is the difference in pressure head, measured by a mercury-oil differential manometer for a 20 cm difference of mercury level? (Specific Gravity of oil = 0.8)a)2.72 m of oilb)2.52 m of oilc)3.40 m of oild)2.00 m of oilCorrect answer is option 'C'. Can you explain this answer?
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What is the difference in pressure head, measured by a mercury-oil differential manometer for a 20 cm difference of mercury level? (Specific Gravity of oil = 0.8)a)2.72 m of oilb)2.52 m of oilc)3.40 m of oild)2.00 m of oilCorrect answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about What is the difference in pressure head, measured by a mercury-oil differential manometer for a 20 cm difference of mercury level? (Specific Gravity of oil = 0.8)a)2.72 m of oilb)2.52 m of oilc)3.40 m of oild)2.00 m of oilCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is the difference in pressure head, measured by a mercury-oil differential manometer for a 20 cm difference of mercury level? (Specific Gravity of oil = 0.8)a)2.72 m of oilb)2.52 m of oilc)3.40 m of oild)2.00 m of oilCorrect answer is option 'C'. Can you explain this answer?.
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