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A piezoelectric type accelerometer has a sensitivity of 100 mV/g. The transducer is subjected to a constant acceleration of 5g. The steady-state output of the transducer will be
- a)0 V
- b)100 mV
- c)0.5 V
- d)5 V
Correct answer is option 'C'. Can you explain this answer?
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A piezoelectric type accelerometer has a sensitivity of 100 mV/g. The ...
Steady state output = sensitivity acceleration
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= 100 mV/g 5g
= 0.5 V.
Most Upvoted Answer
A piezoelectric type accelerometer has a sensitivity of 100 mV/g. The ...
**Answer:**
To understand why the steady-state output of the piezoelectric accelerometer in this scenario is 0.5 V, we need to consider the sensitivity of the accelerometer and the applied constant acceleration.
**1. Understanding Sensitivity:**
The sensitivity of an accelerometer is a measure of how much voltage output it produces per unit of acceleration. In this case, the sensitivity is given as 100 mV/g, which means that for every 1 g of acceleration, the accelerometer produces an output of 100 mV.
**2. Calculation of Steady-State Output:**
Given that the applied constant acceleration is 5 g, we can calculate the steady-state output of the accelerometer using the sensitivity.
Steady-State Output = Sensitivity * Applied Acceleration
In this case, the steady-state output would be:
Steady-State Output = 100 mV/g * 5 g = 500 mV
**3. Conversion of Steady-State Output to Volts:**
The steady-state output of 500 mV needs to be converted to volts. Since 1 V is equal to 1000 mV, the steady-state output in volts would be:
Steady-State Output (V) = 500 mV / 1000 = 0.5 V
Therefore, the steady-state output of the piezoelectric accelerometer in this scenario is 0.5 V, which is option C.
To understand why the steady-state output of the piezoelectric accelerometer in this scenario is 0.5 V, we need to consider the sensitivity of the accelerometer and the applied constant acceleration.
**1. Understanding Sensitivity:**
The sensitivity of an accelerometer is a measure of how much voltage output it produces per unit of acceleration. In this case, the sensitivity is given as 100 mV/g, which means that for every 1 g of acceleration, the accelerometer produces an output of 100 mV.
**2. Calculation of Steady-State Output:**
Given that the applied constant acceleration is 5 g, we can calculate the steady-state output of the accelerometer using the sensitivity.
Steady-State Output = Sensitivity * Applied Acceleration
In this case, the steady-state output would be:
Steady-State Output = 100 mV/g * 5 g = 500 mV
**3. Conversion of Steady-State Output to Volts:**
The steady-state output of 500 mV needs to be converted to volts. Since 1 V is equal to 1000 mV, the steady-state output in volts would be:
Steady-State Output (V) = 500 mV / 1000 = 0.5 V
Therefore, the steady-state output of the piezoelectric accelerometer in this scenario is 0.5 V, which is option C.
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A piezoelectric type accelerometer has a sensitivity of 100 mV/g. The transducer is subjected to a constant acceleration of 5g. The steady-state output of the transducer will bea)0 Vb)100 mVc)0.5 Vd)5 VCorrect answer is option 'C'. Can you explain this answer?
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