A 2cm long coil has 10 t runs and curries a current of 750 MA. The ma...
Where:
L is in Henries
N is the Number of Turns
is the Magnetic Flux Linkage
Ι is in Amperes
This expression can also be defined as the flux linkage divided by the current flowing through each turn. This equation only applies to linear magnetic materials.
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A 2cm long coil has 10 t runs and curries a current of 750 MA. The ma...
Magnetizing Force of a Coil
To understand the given question, let's break it down and discuss the important concepts related to magnetizing force and coils.
1. Magnetizing Force:
- The magnetizing force (H) is a measure of the magnetic field strength produced by a magnetic field source, such as a coil.
- It is given by the equation H = (N * I) / l, where N is the number of turns, I is the current, and l is the length of the coil.
2. Coil Parameters:
- Length of the coil (l): The given coil has a length of 2 cm, which can be converted to meters as 0.02 m.
- Number of turns (N): The coil has 10 turns.
- Current (I): The coil carries a current of 750 mA, which can be converted to amperes as 0.75 A.
Calculation of Magnetizing Force:
Using the given parameters, we can calculate the magnetizing force (H) of the coil.
H = (N * I) / l
= (10 * 0.75) / 0.02
= 7.5 / 0.02
= 375 A/m (Ampere per meter)
Therefore, the magnetizing force of the coil is 375 A/m.
Explanation of the Correct Answer:
The correct answer is option 'D' (375 AT/M), which matches the calculated magnetizing force of 375 A/m. Thus, the answer is correct.
It is important to note that the unit "AT/M" mentioned in the options is an incorrect unit for magnetizing force. The correct unit is "A/m" - Ampere per meter.
Hence, the correct answer is option 'D' (375 A/m), which represents the magnetizing force of the coil.