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A 2cm long coil has 10 t runs and curries a current of 750 MA. The magnetizing force of the coilis
- a)225 AT/M
- b)675 AT/M
- c)450 AT/M
- d)375 AT/M
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A 2cm long coil has 10 t runs and curries a current of 750 MA. The ma...
Where:
L is in Henries
N is the Number of Turns
is the Magnetic Flux LinkageΙ is in Amperes
This expression can also be defined as the flux linkage divided by the current flowing through each turn. This equation only applies to linear magnetic materials.
Most Upvoted Answer
A 2cm long coil has 10 t runs and curries a current of 750 MA. The ma...
Magnetizing Force of a Coil
To understand the given question, let's break it down and discuss the important concepts related to magnetizing force and coils.
1. Magnetizing Force:
- The magnetizing force (H) is a measure of the magnetic field strength produced by a magnetic field source, such as a coil.
- It is given by the equation H = (N * I) / l, where N is the number of turns, I is the current, and l is the length of the coil.
2. Coil Parameters:
- Length of the coil (l): The given coil has a length of 2 cm, which can be converted to meters as 0.02 m.
- Number of turns (N): The coil has 10 turns.
- Current (I): The coil carries a current of 750 mA, which can be converted to amperes as 0.75 A.
Calculation of Magnetizing Force:
Using the given parameters, we can calculate the magnetizing force (H) of the coil.
H = (N * I) / l
= (10 * 0.75) / 0.02
= 7.5 / 0.02
= 375 A/m (Ampere per meter)
Therefore, the magnetizing force of the coil is 375 A/m.
Explanation of the Correct Answer:
The correct answer is option 'D' (375 AT/M), which matches the calculated magnetizing force of 375 A/m. Thus, the answer is correct.
It is important to note that the unit "AT/M" mentioned in the options is an incorrect unit for magnetizing force. The correct unit is "A/m" - Ampere per meter.
Hence, the correct answer is option 'D' (375 A/m), which represents the magnetizing force of the coil.
To understand the given question, let's break it down and discuss the important concepts related to magnetizing force and coils.
1. Magnetizing Force:
- The magnetizing force (H) is a measure of the magnetic field strength produced by a magnetic field source, such as a coil.
- It is given by the equation H = (N * I) / l, where N is the number of turns, I is the current, and l is the length of the coil.
2. Coil Parameters:
- Length of the coil (l): The given coil has a length of 2 cm, which can be converted to meters as 0.02 m.
- Number of turns (N): The coil has 10 turns.
- Current (I): The coil carries a current of 750 mA, which can be converted to amperes as 0.75 A.
Calculation of Magnetizing Force:
Using the given parameters, we can calculate the magnetizing force (H) of the coil.
H = (N * I) / l
= (10 * 0.75) / 0.02
= 7.5 / 0.02
= 375 A/m (Ampere per meter)
Therefore, the magnetizing force of the coil is 375 A/m.
Explanation of the Correct Answer:
The correct answer is option 'D' (375 AT/M), which matches the calculated magnetizing force of 375 A/m. Thus, the answer is correct.
It is important to note that the unit "AT/M" mentioned in the options is an incorrect unit for magnetizing force. The correct unit is "A/m" - Ampere per meter.
Hence, the correct answer is option 'D' (375 A/m), which represents the magnetizing force of the coil.
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A 2cm long coil has 10 t runs and curries a current of 750 MA. The magnetizing force of the coilisa)225 AT/Mb)675 AT/Mc)450 AT/Md)375 AT/MCorrect answer is option 'D'. Can you explain this answer?
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