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Consider a simple closed chain mechanism of n links with one of the links fixed. What is the total number of Instantaneous center of rotations possible for the mechanism?
  • a)
    n!
  • b)
    n(n-1)/2
  • c)
    (n-1)(n-2)/2
  • d)
    n2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Consider a simple closed chain mechanism of n links with one of the l...
An Instantaneous center of rotation forms for every 2 links in combination.
The total number of Instantaneous center of rotations is equal to combining two links out of n links.
So nC2 = n(n-1)/2
Mistake: Don’t confuse here that as one link is fixed so the Instantaneous center of rotations will vanish, and the answer you will get is n-1C2 = (n-1)(n-2)/2. This is incorrect.
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Consider a simple closed chain mechanism of n links with one of the links fixed. What is the total number of Instantaneous center of rotations possible for the mechanism?a)n!b)n(n-1)/2c)(n-1)(n-2)/2d)n2Correct answer is option 'B'. Can you explain this answer?
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