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A body Slipping on a rough horizontal plane moves with a deceleration of 5 ms-2. What is the coefficient of kinetic friction between the block and the plane? (g = 10 ms-2)
- a)0.5
- b)0.4
- c)0.2
- d)0.25
Correct answer is option 'A'. Can you explain this answer?
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A body Slipping on a rough horizontal plane moves with a deceleration...
Let F be the frictional force, N is the normal force, and μk be the coefficient of kinetic friction.
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A body Slipping on a rough horizontal plane moves with a deceleration...
To find the coefficient of kinetic friction between the block and the plane, we can use the formula:
μ = a/g
where:
μ is the coefficient of kinetic friction,
a is the deceleration of the block, and
g is the acceleration due to gravity.
Given that the deceleration of the block is 5 m/s² and the acceleration due to gravity is 10 m/s², we can substitute these values into the formula to find the coefficient of kinetic friction.
Solution:
Given:
Deceleration of the block (a) = 5 m/s²
Acceleration due to gravity (g) = 10 m/s²
To find:
Coefficient of kinetic friction (μ)
Using the formula:
μ = a/g
Substituting the given values:
μ = 5/10
μ = 0.5
Therefore, the coefficient of kinetic friction between the block and the plane is 0.5.
Explanation:
The coefficient of kinetic friction is a measure of how rough or smooth the surfaces in contact are. It represents the ratio of the force of friction to the normal force between two objects in contact.
In this case, the block is slipping on a rough horizontal plane, so there is a force of friction acting in the opposite direction of motion. The deceleration of the block is caused by this frictional force.
The formula μ = a/g relates the deceleration of the block to the coefficient of kinetic friction and the acceleration due to gravity. By substituting the given values into the formula, we can calculate the coefficient of kinetic friction.
In this question, the deceleration of the block is given as 5 m/s² and the acceleration due to gravity is 10 m/s². Therefore, the coefficient of kinetic friction is calculated to be 0.5.
This means that the force of friction between the block and the plane is half of the normal force. The higher the coefficient of kinetic friction, the rougher the surfaces in contact are, and the greater the force of friction.
μ = a/g
where:
μ is the coefficient of kinetic friction,
a is the deceleration of the block, and
g is the acceleration due to gravity.
Given that the deceleration of the block is 5 m/s² and the acceleration due to gravity is 10 m/s², we can substitute these values into the formula to find the coefficient of kinetic friction.
Solution:
Given:
Deceleration of the block (a) = 5 m/s²
Acceleration due to gravity (g) = 10 m/s²
To find:
Coefficient of kinetic friction (μ)
Using the formula:
μ = a/g
Substituting the given values:
μ = 5/10
μ = 0.5
Therefore, the coefficient of kinetic friction between the block and the plane is 0.5.
Explanation:
The coefficient of kinetic friction is a measure of how rough or smooth the surfaces in contact are. It represents the ratio of the force of friction to the normal force between two objects in contact.
In this case, the block is slipping on a rough horizontal plane, so there is a force of friction acting in the opposite direction of motion. The deceleration of the block is caused by this frictional force.
The formula μ = a/g relates the deceleration of the block to the coefficient of kinetic friction and the acceleration due to gravity. By substituting the given values into the formula, we can calculate the coefficient of kinetic friction.
In this question, the deceleration of the block is given as 5 m/s² and the acceleration due to gravity is 10 m/s². Therefore, the coefficient of kinetic friction is calculated to be 0.5.
This means that the force of friction between the block and the plane is half of the normal force. The higher the coefficient of kinetic friction, the rougher the surfaces in contact are, and the greater the force of friction.
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A body Slipping on a rough horizontal plane moves with a deceleration of 5 ms-2. What is the coefficient of kinetic friction between the block and the plane? (g = 10 ms-2)a)0.5b)0.4c)0.2d)0.25Correct answer is option 'A'. Can you explain this answer?
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