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At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The square
undergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shown
in the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εy
and shear strain γxy developed in the square respectively are
undergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shown
in the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εy
and shear strain γxy developed in the square respectively are
- a)-0.0020,0.0025and0.0020
- b)0.0020,0.0025and0.0020
- c)0.0025,0.0020 and 0.0020
- d)-0.0020,0.0025 and 0.0020
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
At a point ‘O’ on a metal sheet a square OABC of a unit si...
The point is to find ex, ey and shear strain, we have to solve the problem by dividing into 3 parts
step1:- find ex
since the square plate is shortened by 0.002mm in X direction ex=0.002/1 . ' . ex=-0.002 ( negative ,since it's shortened).
step 2:- find ey
since the square plate is elongated by 0.0025mm in y direction ey=0.0025/1 . ' . ey=0.0025 ( here it's positive).
step 3:- find shear strain
here, the square plate is distorted in both directions
#for a positive face positive direction forces, it's
shear strain =0.001/1 .'. shear strain =+0.001.
#for positive face negative direction forces, it's
shear strain=0.003/1 .'. shear strain=-0.003( reason for negative is above sentence).
so total strain = -0.002
so the option is d.)
step1:- find ex
since the square plate is shortened by 0.002mm in X direction ex=0.002/1 . ' . ex=-0.002 ( negative ,since it's shortened).
step 2:- find ey
since the square plate is elongated by 0.0025mm in y direction ey=0.0025/1 . ' . ey=0.0025 ( here it's positive).
step 3:- find shear strain
here, the square plate is distorted in both directions
#for a positive face positive direction forces, it's
shear strain =0.001/1 .'. shear strain =+0.001.
#for positive face negative direction forces, it's
shear strain=0.003/1 .'. shear strain=-0.003( reason for negative is above sentence).
so total strain = -0.002
so the option is d.)
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At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer?
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At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer?.
At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At a point ‘O’ on a metal sheet a square OABC of a unit side length is drawn. The squareundergoes a small uniform elastic deformation and deforms to OA*B*C* (dashed lines) as shownin the figure. All dimensions are in mm and the figure is not to scale. The normal strains εx , εyand shear strain γxy developed in the square respectively area)-0.0020,0.0025and0.0020b)0.0020,0.0025and0.0020c)0.0025,0.0020 and 0.0020d)-0.0020,0.0025 and 0.0020Correct answer is option 'D'. Can you explain this answer?.
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