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A multiple – disc clutch transmits 50 kw of power at 1400 rom. Axial intensity of pressure not to exceed 0.12 1 N/mm2, and the coefficient of friction of the friction surfaces is 0.12. the inner radius of the discs is 80 mm, and is .7 times the outer radius. Determine number of disc required to transmit the given power. Assume uniform wear condition.?
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A multiple – disc clutch transmits 50 kw of power at 1400 rom. Axial i...
Calculation of Number of Discs Required in a Multiple-Disc Clutch


Given Data:


  • Power transmitted (P) = 50 kW

  • Speed (N) = 1400 rpm

  • Axial intensity of pressure (p) = 0.12 N/mm2

  • Coefficient of friction (μ) = 0.12

  • Inner radius of discs (r1) = 80 mm

  • Outer radius of discs (r2) = 1.4 * r1 = 112 mm



Formula Used:


  • Power transmitted (P) = 2 * π * N * T / 60

  • Axial force (F) = π * (r22 - r12) * p

  • Torque (T) = F * μ * rm

  • Number of discs (n) = (P * 60) / (2 * π * N * T)



Calculation:


  • From the given data, r1 = 80 mm and r2 = 112 mm

  • Mean radius (rm) = (r1 + r2) / 2 = 96 mm

  • Speed (N) is given in rpm, so it needs to be converted to rad/s

  • N = 1400 rpm = (1400 / 60) rad/s = 23.33 rad/s

  • Axial force (F) = π * (r22 - r12) * p = π * (1122 - 802) * 0.12 = 2755.2 N

  • Torque (T) = F * μ * rm = 2755.2 * 0.12 * 96 = 31623.552 N-mm

  • Number of discs (n) = (P * 60) / (2 * π * N * T) = (50 * 60) / (2 * π * 23.33 * 31623.552) = 2.35



Answer:

Therefore, the number of discs required in the multiple-disc clutch is 3 (since the number of discs needs to be a whole number). This means that the clutch will have 3 pairs of friction surfaces, with each pair consisting of an inner and outer disc.
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A multiple – disc clutch transmits 50 kw of power at 1400 rom. Axial intensity of pressure not to exceed 0.12 1 N/mm2, and the coefficient of friction of the friction surfaces is 0.12. the inner radius of the discs is 80 mm, and is .7 times the outer radius. Determine number of disc required to transmit the given power. Assume uniform wear condition.?
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A multiple – disc clutch transmits 50 kw of power at 1400 rom. Axial intensity of pressure not to exceed 0.12 1 N/mm2, and the coefficient of friction of the friction surfaces is 0.12. the inner radius of the discs is 80 mm, and is .7 times the outer radius. Determine number of disc required to transmit the given power. Assume uniform wear condition.? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A multiple – disc clutch transmits 50 kw of power at 1400 rom. Axial intensity of pressure not to exceed 0.12 1 N/mm2, and the coefficient of friction of the friction surfaces is 0.12. the inner radius of the discs is 80 mm, and is .7 times the outer radius. Determine number of disc required to transmit the given power. Assume uniform wear condition.? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A multiple – disc clutch transmits 50 kw of power at 1400 rom. Axial intensity of pressure not to exceed 0.12 1 N/mm2, and the coefficient of friction of the friction surfaces is 0.12. the inner radius of the discs is 80 mm, and is .7 times the outer radius. Determine number of disc required to transmit the given power. Assume uniform wear condition.?.
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