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Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (given pKa of acetic acid is 4.74)?
Most Upvoted Answer
Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (g...
Solution:

Given,
Volume of CH3COOH solution = 500 mL
Concentration of CH3COOH solution = 0.1 M
Volume of NaOH solution = 250 mL
Concentration of NaOH solution = 0.1 M
pKa of acetic acid = 4.74

Step 1: Write the balanced chemical equation for the reaction between CH3COOH and NaOH.

CH3COOH + NaOH → NaCH3COO + H2O

Step 2: Calculate the number of moles of CH3COOH and NaOH.

Number of moles of CH3COOH = Molarity × Volume (in liters) = 0.1 × 0.5 = 0.05 moles
Number of moles of NaOH = Molarity × Volume (in liters) = 0.1 × 0.25 = 0.025 moles

Step 3: Determine the limiting reagent.

Since NaOH is present in a lesser amount than CH3COOH, it is the limiting reagent.

Step 4: Calculate the number of moles of NaCH3COO formed.

From the balanced chemical equation, the stoichiometric ratio between NaOH and NaCH3COO is 1:1. Therefore, the number of moles of NaCH3COO formed is also 0.025 moles.

Step 5: Calculate the concentration of the resulting solution.

Total volume of the resulting solution = Volume of CH3COOH solution + Volume of NaOH solution = 500 mL + 250 mL = 750 mL = 0.75 L

Concentration of NaCH3COO = Number of moles of NaCH3COO / Total volume of the resulting solution = 0.025 / 0.75 = 0.033 M

Step 6: Calculate the pH of the resulting solution.

Using the Henderson-Hasselbalch equation,

pH = pKa + log ([A-]/[HA])

where [A-] is the concentration of NaCH3COO and [HA] is the concentration of CH3COOH.

Substituting the values,

pH = 4.74 + log (0.033/0.05)

pH = 4.74 - 0.23

pH = 4.51

Therefore, the pH of the resulting solution is 4.51.

Conclusion:

The pH of the mixture of 500 mL 0.1 M CH3COOH and 250 mL 0.1 M NaOH solution is 4.51.
Community Answer
Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (g...
PH will be same 4.74 . if yes then ask me solution of this on telegram here I am unable to send. my I'd
https://t.me/rajeev1029kumar
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Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (given pKa of acetic acid is 4.74)?
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Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (given pKa of acetic acid is 4.74)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (given pKa of acetic acid is 4.74)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ph of mixture of 500ml 0.1M ch3cooh and 250ml 0.1M Naoh Solution is (given pKa of acetic acid is 4.74)?.
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