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The density of a liquid is 1.2 gm / ml3, if there are 35 drops of 2 ml then multiply the number of atoms in one drop. (Molecular weight = 70 u)?
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The density of a liquid is 1.2 gm / ml3, if there are 35 drops of 2 ml...

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The density of a liquid is defined as the mass of the liquid per unit volume. In this case, the density of the liquid is 1.2 g/mL.

The number of drops of 2 mL is 35. This means that the total volume of the liquid is 35 * 2 mL = 70 mL.

The mass of the liquid is equal to its density multiplied by its volume. So the mass of the liquid is 1.2 g/mL * 70 mL = 84 g.

The molecular weight of the liquid is 70 u. This means that one molecule of the liquid has a mass of 70 u.

The number of molecules in one drop of the liquid is equal to the mass of the liquid in one drop divided by the mass of one molecule. So the number of molecules in one drop is 84 g / 70 u * 6.022 * 10^23 molecules/u = 1.7 * 10^23 molecules.

Therefore, the number of atoms in one drop is 2 * 1.7 * 10^23 = 3.4 * 10^23 atoms.

So the answer is 3.4 * 10^23
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The density of a liquid is 1.2 gm / ml3, if there are 35 drops of 2 ml then multiply the number of atoms in one drop. (Molecular weight = 70 u)?
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