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A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)
- a)0.55
- b)0.10
- c)0.64
- d)0.75
Correct answer is option 'C'. Can you explain this answer?
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A mild steel wire is 10mm in diameter and 1mm long. If the wire is su...
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A mild steel wire is 10mm in diameter and 1mm long. If the wire is su...
To find the extension of the road, we can use the formula for axial strain:
Strain (ε) = Extension (ΔL) / Original Length (L)
We can rearrange this formula to solve for the extension:
Extension (ΔL) = Strain (ε) * Original Length (L)
To calculate the strain, we can use the formula for axial stress:
Stress (σ) = Force (F) / Area (A)
We can rearrange this formula to solve for the area:
Area (A) = Force (F) / Stress (σ)
Since the wire is in tension, the stress is equal to the force divided by the cross-sectional area of the wire:
Stress (σ) = Force (F) / (π * (diameter/2)^2)
Now we can substitute the given values into the formula:
Stress (σ) = 10kN / (π * (10mm/2)^2) = 10,000 N / (π * 5mm^2) = 10,000 N / (π * 25mm^2) = 10,000 N / (π * 625mm^2) ≈ 5.093 N/mm^2
Next, we can calculate the strain:
Strain (ε) = Stress (σ) / Young's Modulus (E)
Strain (ε) = 5.093 N/mm^2 / (200 x 10^9 N/mm^2) = 5.093 x 10^-9
Finally, we can calculate the extension:
Extension (ΔL) = Strain (ε) * Original Length (L) = 5.093 x 10^-9 * 1mm = 5.093 x 10^-9 mm
Converting the extension from millimeters to meters:
Extension (ΔL) = 5.093 x 10^-9 mm * (1 m / 1000 mm) = 5.093 x 10^-12 m
Therefore, the extension of the road is approximately 5.093 x 10^-12 meters.
Since none of the given options matches this answer, there might be an error in the question or the options provided.
Strain (ε) = Extension (ΔL) / Original Length (L)
We can rearrange this formula to solve for the extension:
Extension (ΔL) = Strain (ε) * Original Length (L)
To calculate the strain, we can use the formula for axial stress:
Stress (σ) = Force (F) / Area (A)
We can rearrange this formula to solve for the area:
Area (A) = Force (F) / Stress (σ)
Since the wire is in tension, the stress is equal to the force divided by the cross-sectional area of the wire:
Stress (σ) = Force (F) / (π * (diameter/2)^2)
Now we can substitute the given values into the formula:
Stress (σ) = 10kN / (π * (10mm/2)^2) = 10,000 N / (π * 5mm^2) = 10,000 N / (π * 25mm^2) = 10,000 N / (π * 625mm^2) ≈ 5.093 N/mm^2
Next, we can calculate the strain:
Strain (ε) = Stress (σ) / Young's Modulus (E)
Strain (ε) = 5.093 N/mm^2 / (200 x 10^9 N/mm^2) = 5.093 x 10^-9
Finally, we can calculate the extension:
Extension (ΔL) = Strain (ε) * Original Length (L) = 5.093 x 10^-9 * 1mm = 5.093 x 10^-9 mm
Converting the extension from millimeters to meters:
Extension (ΔL) = 5.093 x 10^-9 mm * (1 m / 1000 mm) = 5.093 x 10^-12 m
Therefore, the extension of the road is approximately 5.093 x 10^-12 meters.
Since none of the given options matches this answer, there might be an error in the question or the options provided.
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A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer?
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A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer?.
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A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A mild steel wire is 10mm in diameter and 1mm long. If the wire is subjected to an axial tensile load of 10kN, find an extension of the road (Take E = 200 x 109.)a)0.55b)0.10c)0.64d)0.75Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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