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Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.?
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Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what po...
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Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what po...
Given:
- Charge 1 (q1) = 5 x 10^(-6) C
- Charge 2 (q2) = -3 x 10^(-6) C
- Distance between the charges (r) = 16 cm = 0.16 m
To find:
- Points on the line joining the charges where the electric potential is zero.
Explanation:
The electric potential at a point due to a single charge can be calculated using the equation:
V = k * (q / r)
where V is the electric potential, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the charge.
To find the points where the electric potential is zero, we need to calculate the electric potential at different points on the line joining the charges and check if it equals zero.
Method:
1. Calculate the electric potential due to charge 1 (V1) and charge 2 (V2) at different points on the line joining the charges.
2. Check if V1 + V2 equals zero at any point.
Calculations:
Let's calculate the electric potential at different points on the line joining the charges:
1. At a point between the charges:
- Let the distance of the point from charge 1 be x.
- The distance of the point from charge 2 is then (0.16 - x).
- The electric potential due to charge 1 (V1) at this point is V1 = (9 x 10^9) * (5 x 10^(-6) / x)
- The electric potential due to charge 2 (V2) at this point is V2 = (9 x 10^9) * (-3 x 10^(-6) / (0.16 - x))
- V1 + V2 = 0
- Simplifying the equation, we get:
(5 / x) - (3 / (0.16 - x)) = 0
Solving this equation will give the value of x.
2. At a point outside the charges:
- Let the distance of the point from charge 1 be y.
- The distance of the point from charge 2 is then (0.16 + y).
- The electric potential due to charge 1 (V1) at this point is V1 = (9 x 10^9) * (5 x 10^(-6) / y)
- The electric potential due to charge 2 (V2) at this point is V2 = (9 x 10^9) * (-3 x 10^(-6) / (0.16 + y))
- V1 + V2 = 0
- Simplifying the equation, we get:
(5 / y) - (3 / (0.16 + y)) = 0
Solving this equation will give the value of y.
Conclusion:
By solving the above equations, we can find the values of x and y, which represent the distances of the points from charge 1. These values will give us the points on the line joining the charges where the electric potential is zero.
- Charge 1 (q1) = 5 x 10^(-6) C
- Charge 2 (q2) = -3 x 10^(-6) C
- Distance between the charges (r) = 16 cm = 0.16 m
To find:
- Points on the line joining the charges where the electric potential is zero.
Explanation:
The electric potential at a point due to a single charge can be calculated using the equation:
V = k * (q / r)
where V is the electric potential, k is the electrostatic constant (9 x 10^9 Nm^2/C^2), q is the charge, and r is the distance from the charge.
To find the points where the electric potential is zero, we need to calculate the electric potential at different points on the line joining the charges and check if it equals zero.
Method:
1. Calculate the electric potential due to charge 1 (V1) and charge 2 (V2) at different points on the line joining the charges.
2. Check if V1 + V2 equals zero at any point.
Calculations:
Let's calculate the electric potential at different points on the line joining the charges:
1. At a point between the charges:
- Let the distance of the point from charge 1 be x.
- The distance of the point from charge 2 is then (0.16 - x).
- The electric potential due to charge 1 (V1) at this point is V1 = (9 x 10^9) * (5 x 10^(-6) / x)
- The electric potential due to charge 2 (V2) at this point is V2 = (9 x 10^9) * (-3 x 10^(-6) / (0.16 - x))
- V1 + V2 = 0
- Simplifying the equation, we get:
(5 / x) - (3 / (0.16 - x)) = 0
Solving this equation will give the value of x.
2. At a point outside the charges:
- Let the distance of the point from charge 1 be y.
- The distance of the point from charge 2 is then (0.16 + y).
- The electric potential due to charge 1 (V1) at this point is V1 = (9 x 10^9) * (5 x 10^(-6) / y)
- The electric potential due to charge 2 (V2) at this point is V2 = (9 x 10^9) * (-3 x 10^(-6) / (0.16 + y))
- V1 + V2 = 0
- Simplifying the equation, we get:
(5 / y) - (3 / (0.16 + y)) = 0
Solving this equation will give the value of y.
Conclusion:
By solving the above equations, we can find the values of x and y, which represent the distances of the points from charge 1. These values will give us the points on the line joining the charges where the electric potential is zero.
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Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.?
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Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.?.
Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two charges 5 x 10"C and -3 x 10 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.?.
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