The sum of magnitude of two forces acting at point is 18 and the mag o...
Explanation:
Given,
- Sum of magnitudes of two forces = 18
- Magnitude of resultant force = 12
- Resultant force makes 90 degrees angle with the force of small magnitude.
Let the two forces be F1 and F2.
Resolve the Resultant force:
We can resolve the resultant force into its components using the following formulae:
R^2 = F1^2 + F2^2 + 2*F1*F2*cosθ
where R is the magnitude of the resultant force, θ is the angle between the two forces
Here, R = 12 and cosθ = 0 (since they are at 90 degrees)
So,
12^2 = F1^2 + F2^2 + 2*F1*F2*0
144 = F1^2 + F2^2
or,
F1^2 + F2^2 = 144 ------(i)
Find the Magnitude of Forces:
From the given data, we know that F1 + F2 = 18
Now, we can use equation (i) to solve for F1 and F2:
Let F1 = x
Then, F2 = 18 - x
Substituting in equation (i), we get:
x^2 + (18 - x)^2 = 144
Simplifying and solving for x, we get:
x = 6 or 12
So, F1 = 6 and F2 = 12 or F1 = 12 and F2 = 6
Therefore, the magnitudes of the forces are 6 N and 12 N or 12 N and 6 N.
Conclusion:
Thus, the magnitudes of the two forces are 6 N and 12 N or 12 N and 6 N.
The sum of magnitude of two forces acting at point is 18 and the mag o...
Let the magnitude of smaller force is P, the magnitude of larger force is Q and the resultant force is R.
As the resultant force makes 90
∘
with the smaller force P then Q forms the hypotenuse of the triangle.
Thus, it can be written as,
Q ^2 −P^2=R^2
Q ^2 −P^2 =(12)^2
Q ^2 −P^2 =144 (1)
The sum of magnitudes of two forces is given as,
P+Q=18
Q=18−P (2)
Substituting the value from equation (2) in equation (1), we get
(18−P) ^2 −P^2 =144
P=5N
Substituting the value of P in equation (1), we get
Q=18−5
=13N
Thus, the magnitude of the forces are 5N and 13N.
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