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The maximum shear force in a cantilever beam with uniformly distributed load W per unit length, over the whole length L, is
- a)At the centre
- b)At the free and
- c)At the fixed end
- d)Can't free
Correct answer is option 'C'. Can you explain this answer?
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The maximum shear force in a cantilever beam with uniformly distribut...
The maximum shear force in a cantilever beam with uniformly distributed load W per unit length, over the whole length L, is at the fixed end.
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The maximum shear force in a cantilever beam with uniformly distribut...
Explanation:
When a cantilever beam is loaded with a uniformly distributed load over its entire length, the maximum shear force will occur at the fixed end. This is because the entire load is being transferred to the fixed end, resulting in the maximum shear force at that point.
To understand this concept more clearly, let's break it down into the following points:
• Cantilever Beam: A cantilever beam is a beam that is supported at one end and free at the other end.
• Uniformly Distributed Load: A uniformly distributed load is a load that is evenly distributed over a given length.
• Maximum Shear Force: The maximum shear force is the maximum force that is applied perpendicular to the longitudinal axis of the beam.
• Fixed End: The fixed end is the end of the cantilever beam that is supported and cannot move.
Now, let's consider the following points to understand why the maximum shear force occurs at the fixed end of a cantilever beam with a uniformly distributed load:
• Load Transfer: When a uniformly distributed load is applied to a cantilever beam, the load is transferred to the fixed end of the beam.
• Shear Force: As the load is transferred to the fixed end, it creates a shear force at that point. The shear force is perpendicular to the longitudinal axis of the beam and is maximum at the fixed end.
• Free End: The free end of the cantilever beam is not supported, so there is no resistance to the load. Therefore, the shear force at the free end is zero.
• Centre: The shear force at the centre of the beam is also zero because the load is evenly distributed and there is no net force acting on the beam at that point.
Therefore, the maximum shear force in a cantilever beam with a uniformly distributed load occurs at the fixed end.
When a cantilever beam is loaded with a uniformly distributed load over its entire length, the maximum shear force will occur at the fixed end. This is because the entire load is being transferred to the fixed end, resulting in the maximum shear force at that point.
To understand this concept more clearly, let's break it down into the following points:
• Cantilever Beam: A cantilever beam is a beam that is supported at one end and free at the other end.
• Uniformly Distributed Load: A uniformly distributed load is a load that is evenly distributed over a given length.
• Maximum Shear Force: The maximum shear force is the maximum force that is applied perpendicular to the longitudinal axis of the beam.
• Fixed End: The fixed end is the end of the cantilever beam that is supported and cannot move.
Now, let's consider the following points to understand why the maximum shear force occurs at the fixed end of a cantilever beam with a uniformly distributed load:
• Load Transfer: When a uniformly distributed load is applied to a cantilever beam, the load is transferred to the fixed end of the beam.
• Shear Force: As the load is transferred to the fixed end, it creates a shear force at that point. The shear force is perpendicular to the longitudinal axis of the beam and is maximum at the fixed end.
• Free End: The free end of the cantilever beam is not supported, so there is no resistance to the load. Therefore, the shear force at the free end is zero.
• Centre: The shear force at the centre of the beam is also zero because the load is evenly distributed and there is no net force acting on the beam at that point.
Therefore, the maximum shear force in a cantilever beam with a uniformly distributed load occurs at the fixed end.
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The maximum shear force in a cantilever beam with uniformly distributed load W per unit length, over the whole length L, isa)At the centreb)At the free andc)At the fixed endd)Can't freeCorrect answer is option 'C'. Can you explain this answer?
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