See,
no. of moles of water in a cup =n
n= 250/18
then, total charge Q = n × Na × ne
= 250/18 × 6.022×10^23 × 1.6×10^-19
= 1.34×10^7 c

Calculating Total Positive Charge in a Cup of Water
Calculating the total positive charge present in a cup of water involves understanding the concept of charge and the composition of water.

Composition of Water
Water is composed of molecules of H2O, which are made up of two hydrogen atoms and one oxygen atom.

Charge of a Water Molecule
Each hydrogen atom in a water molecule has a positive charge of +1, while the oxygen atom has a negative charge of -2. This results in a net charge of zero for a water molecule.

Total Positive Charge in a Cup of Water
Given that the cup contains 250 g of water, we can calculate the number of water molecules present in the cup.
- The molar mass of water is approximately 18 g/mol.
- Therefore, the number of moles of water in 250 g is 250/18 ≈ 13.89 mol.
- Since each water molecule has two hydrogen atoms with a positive charge of +1, the total positive charge per water molecule is +2.
- The total positive charge in the cup can be calculated by multiplying the total number of water molecules by the positive charge per molecule.
- Total positive charge = 13.89 mol * 6.022 x 10^23 molecules/mol * +2 = 1.67 x 10^25 charges.
Therefore, the total positive charge present in a cup of water containing 250 g of water is approximately 1.67 x 10^25 charges.