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A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).
Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer?
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A thin-walled tube with external radius of 100 mm and wall thickness o...
Given data:
External radius of the tube, rext = 100 mm = 0.1 m
Wall thickness, t = 2 mm = 0.002 m
Force applied, F = 1 N
Formula:
The maximum normal stress, σmax, can be calculated using the formula:
σmax = F / A
Where,
A = π[(rext)² - (rint)²]
rint = rext - t
Calculation:
Given that the external radius of the tube is 0.1 m and the wall thickness is 0.002 m. Therefore, the internal radius of the tube is:
rint = rext - t
= 0.1 - 0.002
= 0.098 m
The cross-sectional area of the tube is:
A = π[(rext)² - (rint)²]
= π[(0.1)² - (0.098)²]
= π[0.01 - 0.009604]
= π(0.000396)
= 0.001243 m²
Now, substituting the values into the formula for maximum normal stress:
σmax = F / A
= 1 / 0.001243
= 803.7 Pa
Converting from Pascal to kilopascal:
σmax = 803.7 / 1000
= 0.8037 kPa
Therefore, the maximum normal stress experienced by the structure is 0.8037 kPa.
Answer:
The maximum normal stress (in kPa) experienced by the structure is 0.80 kPa (approx).
External radius of the tube, rext = 100 mm = 0.1 m
Wall thickness, t = 2 mm = 0.002 m
Force applied, F = 1 N
Formula:
The maximum normal stress, σmax, can be calculated using the formula:
σmax = F / A
Where,
A = π[(rext)² - (rint)²]
rint = rext - t
Calculation:
Given that the external radius of the tube is 0.1 m and the wall thickness is 0.002 m. Therefore, the internal radius of the tube is:
rint = rext - t
= 0.1 - 0.002
= 0.098 m
The cross-sectional area of the tube is:
A = π[(rext)² - (rint)²]
= π[(0.1)² - (0.098)²]
= π[0.01 - 0.009604]
= π(0.000396)
= 0.001243 m²
Now, substituting the values into the formula for maximum normal stress:
σmax = F / A
= 1 / 0.001243
= 803.7 Pa
Converting from Pascal to kilopascal:
σmax = 803.7 / 1000
= 0.8037 kPa
Therefore, the maximum normal stress experienced by the structure is 0.8037 kPa.
Answer:
The maximum normal stress (in kPa) experienced by the structure is 0.80 kPa (approx).
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A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer?
Question Description
A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer?.
A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin-walled tube with external radius of 100 mm and wall thickness of 2 mm, is fixed at one end. It is subjected to a compressive force of 1 N acting at a point on the circumference parallel to its length. The maximum normal stress (in kPa) experienced by the structure is _____________ (accurate to two decimal places).Correct answer is '‐2.50 to ‐2.20'. Can you explain this answer?.
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