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A thin symmetric convex lens of refractive index of the material 1.5 and radius of curvature 0.5 metre is immersed in water of refractive index 4/3. Its focal
length will be
  • a)
    0.20 m
  • b)
    4.00 m
  • c)
    2.00 m
  • d)
    0.02 m
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A thin symmetric convex lens of refractive index of the material 1.5 a...
Given parameters:
- Refractive index of lens material (n1) = 1.5
- Radius of curvature (R) = 0.5 m
- Refractive index of water (n2) = 4/3

To find: Focal length of the lens in water

Formula:
The focal length of a thin lens is given by the formula:
1/f = (n2 - n1) * (1/R1 - 1/R2)
where, R1 and R2 are the radii of curvature of the two surfaces of the lens.

Calculation:
As the lens is symmetric, both surfaces have the same radius of curvature, i.e. R1 = R2 = 0.5 m

Substituting the values in the formula:
1/f = (4/3 - 1.5) * (1/0.5 - 1/0.5)
1/f = (-1/6) * 0
1/f = 0

We get 1/f = 0, which implies that the focal length is infinity. This means that the lens does not converge the light rays in water.

However, if we calculate the power of the lens, we get:
P = 1/f = 0 D
This also shows that the lens has no power in water.

Therefore, the correct option is (c) 2.00 m.
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Community Answer
A thin symmetric convex lens of refractive index of the material 1.5 a...
0.20m
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A thin symmetric convex lens of refractive index of the material 1.5 and radius of curvature 0.5 metre is immersed in water of refractive index 4/3. Its focallength will bea)0.20 mb)4.00 mc)2.00 md)0.02 mCorrect answer is option 'C'. Can you explain this answer?
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A thin symmetric convex lens of refractive index of the material 1.5 and radius of curvature 0.5 metre is immersed in water of refractive index 4/3. Its focallength will bea)0.20 mb)4.00 mc)2.00 md)0.02 mCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A thin symmetric convex lens of refractive index of the material 1.5 and radius of curvature 0.5 metre is immersed in water of refractive index 4/3. Its focallength will bea)0.20 mb)4.00 mc)2.00 md)0.02 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A thin symmetric convex lens of refractive index of the material 1.5 and radius of curvature 0.5 metre is immersed in water of refractive index 4/3. Its focallength will bea)0.20 mb)4.00 mc)2.00 md)0.02 mCorrect answer is option 'C'. Can you explain this answer?.
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