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The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine is
- a)Greater than T
- b)Less than T
- c)Equal to T
- d)Cannot be compared
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
The period of oscillation of a simple pendulum of constant length at e...
A is correct answer because time period of oscillation of simple pendulum T =2π √l/g
it means time period of oscillation is inversely proportional to root of acceleration due to gravity.
and we know that in mine acceleration due to gravity
g' = g (1- d/R)
now u can understand that in the mine acceleration due gravity decrease that's why Time period increase..it means greater than T
it means time period of oscillation is inversely proportional to root of acceleration due to gravity.
and we know that in mine acceleration due to gravity
g' = g (1- d/R)
now u can understand that in the mine acceleration due gravity decrease that's why Time period increase..it means greater than T
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The period of oscillation of a simple pendulum of constant length at e...
Explanation:
Period of a Simple Pendulum:
The period of a simple pendulum is the time taken for one complete oscillation, which is the time taken for the pendulum to swing from one extreme position to the other and back again.
Factors affecting the Period of a Simple Pendulum:
The period of a simple pendulum depends on two main factors:
1. Length of the pendulum: The longer the length, the longer the period.
2. Acceleration due to gravity: The greater the acceleration due to gravity, the shorter the period.
The Relationship between Length and Period:
The period of a simple pendulum is directly proportional to the square root of its length. Mathematically, we can express this relationship as:
T ∝ √L
The Effect of the Mine on the Period:
When the simple pendulum is taken inside a mine, the length of the pendulum remains constant. However, the acceleration due to gravity changes inside the mine.
Inside the mine, the acceleration due to gravity is less than the acceleration due to gravity on the Earth's surface. This is because the mine is located below the surface where the gravitational force is slightly weaker.
Effect on the Period:
As mentioned earlier, the period of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity.
Inside the mine, the acceleration due to gravity is smaller than on the Earth's surface. Therefore, the period of the pendulum inside the mine will be larger than the period on the Earth's surface.
Conclusion:
Hence, we can conclude that the period of oscillation of a simple pendulum inside a mine is greater than the period on the Earth's surface. Therefore, the correct answer is option 'A' - Greater than T.
Period of a Simple Pendulum:
The period of a simple pendulum is the time taken for one complete oscillation, which is the time taken for the pendulum to swing from one extreme position to the other and back again.
Factors affecting the Period of a Simple Pendulum:
The period of a simple pendulum depends on two main factors:
1. Length of the pendulum: The longer the length, the longer the period.
2. Acceleration due to gravity: The greater the acceleration due to gravity, the shorter the period.
The Relationship between Length and Period:
The period of a simple pendulum is directly proportional to the square root of its length. Mathematically, we can express this relationship as:
T ∝ √L
The Effect of the Mine on the Period:
When the simple pendulum is taken inside a mine, the length of the pendulum remains constant. However, the acceleration due to gravity changes inside the mine.
Inside the mine, the acceleration due to gravity is less than the acceleration due to gravity on the Earth's surface. This is because the mine is located below the surface where the gravitational force is slightly weaker.
Effect on the Period:
As mentioned earlier, the period of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity.
Inside the mine, the acceleration due to gravity is smaller than on the Earth's surface. Therefore, the period of the pendulum inside the mine will be larger than the period on the Earth's surface.
Conclusion:
Hence, we can conclude that the period of oscillation of a simple pendulum inside a mine is greater than the period on the Earth's surface. Therefore, the correct answer is option 'A' - Greater than T.
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The period of oscillation of a simple pendulum of constant length at earth surface is T. Its period inside a mine isa)Greater than Tb)Less than Tc)Equal to Td)Cannot be comparedCorrect answer is option 'A'. Can you explain this answer?
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