Reaction of Chloroform with Alcoholic KOH and P-toluidine
The reaction of chloroform with alcoholic KOH and P-toluidine forms a compound known as isocyanide. This reaction proceeds through the formation of the intermediate carbamoyl chloride.

Formation of Carbamoyl Chloride
1. The first step involves the reaction between chloroform (CHCl3) and alcoholic KOH (potassium hydroxide) to form potassium chloride (KCl) and potassium hydroxychloroformate as an intermediate.
2. The intermediate potassium hydroxychloroformate then reacts with P-toluidine to form carbamoyl chloride.

Formation of Isocyanide
3. The carbamoyl chloride further reacts with alcoholic KOH to form the desired isocyanide compound.

Explanation
- The reaction of chloroform with alcoholic KOH and P-toluidine is a multistep process that involves the formation of intermediate compounds before yielding the final product.
- The interaction between the reagents results in the conversion of chloroform to isocyanide through the generation of carbamoyl chloride.
- This reaction pathway is essential for the synthesis of isocyanide compounds, which have various applications in organic chemistry and pharmaceutical research.
This reaction showcases the versatility of chloroform as a starting material in organic synthesis and highlights the importance of understanding reaction mechanisms for the design and development of new compounds.

Para-isocyano methyl benzene