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The shape of IF7 molecule is
- a)Pentagonal bipyramidal
- b)Trigonal bipyramidal
- c)octagonal
- d)T shaped
Correct answer is option 'A'. Can you explain this answer?
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The shape of IF7 molecule isa) Pentag...
Shape of IF7 Molecule
The shape of the IF7 molecule is pentagonal bipyramidal.
Explanation:
To understand the shape of the IF7 molecule, let's first look at its Lewis structure.
IF7 has 7 valence electrons in the outermost shell of the iodine atom and 1 valence electron from each of the 7 fluorine atoms. This gives a total of 14 valence electrons for the molecule.
To draw the Lewis structure, first, we place the iodine atom in the center and surround it with the 7 fluorine atoms. Each fluorine atom forms a single bond with the iodine atom. This uses up 7 of the 14 valence electrons.
Next, we place the remaining 7 electrons as three lone pairs on three of the seven fluorine atoms.
The resulting Lewis structure shows that the IF7 molecule has a pentagonal bipyramidal shape.
This means that the molecule has a central iodine atom with five surrounding fluorine atoms arranged in a pentagonal shape around the central iodine atom. The remaining two fluorine atoms are located above and below the pentagon.
Overall, the IF7 molecule has a symmetrical shape and is considered to be a highly polar molecule due to the electronegativity difference between the iodine and fluorine atoms.
The shape of the IF7 molecule is pentagonal bipyramidal.
Explanation:
To understand the shape of the IF7 molecule, let's first look at its Lewis structure.
IF7 has 7 valence electrons in the outermost shell of the iodine atom and 1 valence electron from each of the 7 fluorine atoms. This gives a total of 14 valence electrons for the molecule.
To draw the Lewis structure, first, we place the iodine atom in the center and surround it with the 7 fluorine atoms. Each fluorine atom forms a single bond with the iodine atom. This uses up 7 of the 14 valence electrons.
Next, we place the remaining 7 electrons as three lone pairs on three of the seven fluorine atoms.
The resulting Lewis structure shows that the IF7 molecule has a pentagonal bipyramidal shape.
This means that the molecule has a central iodine atom with five surrounding fluorine atoms arranged in a pentagonal shape around the central iodine atom. The remaining two fluorine atoms are located above and below the pentagon.
Overall, the IF7 molecule has a symmetrical shape and is considered to be a highly polar molecule due to the electronegativity difference between the iodine and fluorine atoms.
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The shape of IF7 molecule isa) Pentag...
IF7 - a molecule with a hybridization of Sp3d3 must have pentagonal bipyramidal shape
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The shape of IF7 molecule isa) Pentagonal bipyramidal b) Trigonal bipyramidal c) octagonal d) T shaped Correct answer is option 'A'. Can you explain this answer?
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