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The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar.
Most Upvoted Answer
The probability of selecting a red ball at random from a jar that cont...
P (getting orange Ball)=1-(1/4 + 1/3)=1-(7/12)=5/12Now,Let Total no. of balls in the Box be 'n'Now,P (Getting orange Ball)=Total no. of orange Balls/ Total no. of balls in the Boxi.e.5/12 = 10/nor,n = (12×10)/5so,n=24Hence, Total number of Balls in the Box=24 Ans.
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The probability of selecting a red ball at random from a jar that cont...
Given Information:
- Probability of selecting a red ball at random from the jar = 1/4
- Probability of selecting a blue ball at random from the jar = 1/3
- Number of orange balls in the jar = 10
To Find:
- Total number of balls in the jar
Solution:
Let's assume the total number of balls in the jar as 'x'.
Probability of Selecting a Red Ball:
The probability of selecting a red ball at random from the jar is given as 1/4.
We can express this probability as the ratio of the number of red balls to the total number of balls in the jar:
1/4 = Number of red balls / x
Probability of Selecting a Blue Ball:
The probability of selecting a blue ball at random from the jar is given as 1/3.
Similarly, we can express this probability as the ratio of the number of blue balls to the total number of balls in the jar:
1/3 = Number of blue balls / x
Number of Orange Balls:
It is given that there are 10 orange balls in the jar.
Sum of Probabilities:
The sum of probabilities of selecting a red ball, a blue ball, and the number of orange balls should equal 1 since we are selecting one ball at random from the jar:
1/4 + 1/3 + 10/x = 1
Solving the Equation:
To solve the equation, we can multiply each term by 12x to eliminate the denominators:
3x + 4x + 120 = 12x
7x + 120 = 12x
120 = 12x - 7x
120 = 5x
Calculating the Total Number of Balls:
Now, we can find the value of 'x' by dividing both sides of the equation by 5:
x = 120 / 5
x = 24
Therefore, the total number of balls in the jar is 24.
- Probability of selecting a red ball at random from the jar = 1/4
- Probability of selecting a blue ball at random from the jar = 1/3
- Number of orange balls in the jar = 10
To Find:
- Total number of balls in the jar
Solution:
Let's assume the total number of balls in the jar as 'x'.
Probability of Selecting a Red Ball:
The probability of selecting a red ball at random from the jar is given as 1/4.
We can express this probability as the ratio of the number of red balls to the total number of balls in the jar:
1/4 = Number of red balls / x
Probability of Selecting a Blue Ball:
The probability of selecting a blue ball at random from the jar is given as 1/3.
Similarly, we can express this probability as the ratio of the number of blue balls to the total number of balls in the jar:
1/3 = Number of blue balls / x
Number of Orange Balls:
It is given that there are 10 orange balls in the jar.
Sum of Probabilities:
The sum of probabilities of selecting a red ball, a blue ball, and the number of orange balls should equal 1 since we are selecting one ball at random from the jar:
1/4 + 1/3 + 10/x = 1
Solving the Equation:
To solve the equation, we can multiply each term by 12x to eliminate the denominators:
3x + 4x + 120 = 12x
7x + 120 = 12x
120 = 12x - 7x
120 = 5x
Calculating the Total Number of Balls:
Now, we can find the value of 'x' by dividing both sides of the equation by 5:
x = 120 / 5
x = 24
Therefore, the total number of balls in the jar is 24.
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The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar.
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The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar. for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar. covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar..
The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar. for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar. covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability of selecting a red ball at random from a jar that contains only red blue and orange balls is 1/4. The probability of selecting a blue ball at random from the same jar is 1/3 . If the jar contains 10 orange balls, find the total number of balls in the jar..
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