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In the Cannizzaro reaction given below 
the slowest step is:
  • a)
    the attack of -OH  at the carbonyl group 
  • b)
    the transfer of hydride ion to the carbonyl group
  • c)
    the abstraction of proton from the carboxylic acid
  • d)
    the deprotonation of Ph - Ch2 OH
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In the Cannizzaro reaction given below the slowest step is:a)the attac...
Rate determining step is always the slowest step. In case of Cannizzaro reaction, H-transfer to the carbonyl group is the rate-determining step and hence the slowest.
This question is part of UPSC exam. View all NEET courses
Most Upvoted Answer
In the Cannizzaro reaction given below the slowest step is:a)the attac...
RDS is always slow
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In the Cannizzaro reaction given below the slowest step is:a)the attack of -OH at the carbonyl groupb)the transfer of hydride ion to the carbonyl groupc)the abstraction of proton from the carboxylic acidd)the deprotonation ofPh - Ch2 OHCorrect answer is option 'B'. Can you explain this answer?
Question Description
In the Cannizzaro reaction given below the slowest step is:a)the attack of -OH at the carbonyl groupb)the transfer of hydride ion to the carbonyl groupc)the abstraction of proton from the carboxylic acidd)the deprotonation ofPh - Ch2 OHCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In the Cannizzaro reaction given below the slowest step is:a)the attack of -OH at the carbonyl groupb)the transfer of hydride ion to the carbonyl groupc)the abstraction of proton from the carboxylic acidd)the deprotonation ofPh - Ch2 OHCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the Cannizzaro reaction given below the slowest step is:a)the attack of -OH at the carbonyl groupb)the transfer of hydride ion to the carbonyl groupc)the abstraction of proton from the carboxylic acidd)the deprotonation ofPh - Ch2 OHCorrect answer is option 'B'. Can you explain this answer?.
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