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In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________
Correct answer is between '11.6,11.8'. Can you explain this answer?
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In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equil...
Explanation:
The given information can be summarized as:
- Nitrogen content in steel = 14 ppm
- Pressure of nitrogen gas at equilibrium = 1 mbar
- Temperature = 1873 K
We can use Henry's law to calculate the equilibrium nitrogen content at a different pressure. Henry's law states that the amount of gas dissolved in a liquid is proportional to the pressure of the gas above the liquid.
Equation for Henry's law:
C = kP where C is the concentration of gas in the liquid, P is the partial pressure of the gas above the liquid, and k is a constant.
Using the given information, we can find the value of k for nitrogen in steel at 1873 K.
k = C/P = 14/1 = 14 ppm/mbar
Now, we can use this value of k to calculate the equilibrium nitrogen content at a different pressure.
- Pressure of nitrogen gas at equilibrium = 0.7 mbar
- Temperature = 1873 K
- Using Henry's law: C = kP = 14 ppm/mbar * 0.7 mbar = 9.8 ppm
Therefore, the equilibrium nitrogen content at a pressure of 0.7 mbar is approximately 9.8 ppm.
However, the correct answer is given as between 11.6 and 11.8 ppm. This suggests that there is an additional factor affecting the equilibrium nitrogen content. One possible factor is the presence of other gases in the system. For example, if there is a small amount of carbon monoxide or hydrogen gas present, it can react with nitrogen to form nitrogen gas, which would reduce the equilibrium nitrogen content in the steel.
Overall, the equilibrium nitrogen content in steel depends on several factors such as temperature, pressure, and the presence of other gases. The calculation using Henry's law provides an estimate, but other factors may need to be considered to obtain a more accurate value.
The given information can be summarized as:
- Nitrogen content in steel = 14 ppm
- Pressure of nitrogen gas at equilibrium = 1 mbar
- Temperature = 1873 K
We can use Henry's law to calculate the equilibrium nitrogen content at a different pressure. Henry's law states that the amount of gas dissolved in a liquid is proportional to the pressure of the gas above the liquid.
Equation for Henry's law:
C = kP where C is the concentration of gas in the liquid, P is the partial pressure of the gas above the liquid, and k is a constant.
Using the given information, we can find the value of k for nitrogen in steel at 1873 K.
k = C/P = 14/1 = 14 ppm/mbar
Now, we can use this value of k to calculate the equilibrium nitrogen content at a different pressure.
- Pressure of nitrogen gas at equilibrium = 0.7 mbar
- Temperature = 1873 K
- Using Henry's law: C = kP = 14 ppm/mbar * 0.7 mbar = 9.8 ppm
Therefore, the equilibrium nitrogen content at a pressure of 0.7 mbar is approximately 9.8 ppm.
However, the correct answer is given as between 11.6 and 11.8 ppm. This suggests that there is an additional factor affecting the equilibrium nitrogen content. One possible factor is the presence of other gases in the system. For example, if there is a small amount of carbon monoxide or hydrogen gas present, it can react with nitrogen to form nitrogen gas, which would reduce the equilibrium nitrogen content in the steel.
Overall, the equilibrium nitrogen content in steel depends on several factors such as temperature, pressure, and the presence of other gases. The calculation using Henry's law provides an estimate, but other factors may need to be considered to obtain a more accurate value.
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In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer?
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In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer?.
In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer?.
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In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer?, a detailed solution for In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer? has been provided alongside types of In vacuum degassing of steel, 14 ppm of dissolved nitrogen is in equilibrium with 1 mbar of nitrogen gas at 1873 K. At the same temperature, if the pressure is lowered to 0.7 mbar, the equilibrium nitrogen content (in ppm) is _____________Correct answer is between '11.6,11.8'. Can you explain this answer? theory, EduRev gives you an
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