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Find Altitude of rhombus if diagonals are 24cm and 32cm respectively?
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Find Altitude of rhombus if diagonals are 24cm and 32cm respectively?

The diagonals of a rhombus bisect each-other at right angles,with the side of the rhombus being the hypotenuse . Half the lengths of the diagonals AO = 12 cm , BO= 16 cm. and the hypotenuse(AB) in right triangle ABO in  rhombus ABCD.
Using Pyhagoras Theorem for the right-angled triangle ABO,
h� = 12� + 16� = 400.
∴ The length of the side of the rhombus is 20 cm.
area of a rhombus = ��d1�d2
are of a rhombus= base � height
∴ comparing both formulas
��24�32 = 20�h    (base is side of the rhombus)
∴ h= 19.2 cm.
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Find Altitude of rhombus if diagonals are 24cm and 32cm respectively?
Altitude of a Rhombus
To find the altitude of a rhombus, we can use the formula: Altitude = (d1 * d2) / 2, where d1 and d2 are the diagonals of the rhombus.

Given:
- Diagonal 1 (d1) = 24 cm
- Diagonal 2 (d2) = 32 cm

Calculating the Altitude:
Altitude = (d1 * d2) / 2
Altitude = (24 * 32) / 2
Altitude = (768) / 2
Altitude = 384 cm
Therefore, the altitude of the rhombus is 384 cm.

Explanation:
- A rhombus is a quadrilateral with all sides of equal length and opposite angles equal to each other.
- The diagonals of a rhombus intersect each other at right angles and bisect each other.
- The altitude of a rhombus is the perpendicular distance between two parallel sides.
- In a rhombus, the diagonals are perpendicular bisectors of each other, dividing the rhombus into four right-angled triangles.
- By using the formula for the area of a rhombus (Area = base * height), we can find the altitude of the rhombus using the lengths of its diagonals.
- In this case, the altitude of the rhombus is calculated as (24 * 32) / 2 = 384 cm.
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Find Altitude of rhombus if diagonals are 24cm and 32cm respectively?
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