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The absorbance of a solution of tryptophan measured at 280 nm in a cuvette of 2.0 cm path length is 0.56 at pH 7. The molar extinction coefficient (e) for tryptophan at 280 nm is 5600 M-1cm-1 at pH 7. The concentration of tryptophan (in µM) in the solution  is _________
Correct answer is '50 to 50'. Can you explain this answer?
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The absorbance of a solution of tryptophan measured at 280 nm in a cuv...
Molarity) in the solution can be calculated using the Beer-Lambert law:

A = εcl

Where A is the absorbance, ε is the molar extinction coefficient, c is the concentration, and l is the path length.

Rearranging the equation, we get:

c = A/(εl)

Substituting the given values, we get:

c = 0.56/(5600 M-1cm-1 x 2.0 cm)

c = 0.00005 M or 50 μM

Therefore, the concentration of tryptophan in the solution is 50 μM.
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The absorbance of a solution of tryptophan measured at 280 nm in a cuvette of 2.0 cm path length is 0.56 at pH 7. The molar extinction coefficient (e) for tryptophan at 280 nm is 5600 M-1cm-1 at pH 7. The concentration of tryptophan (in µM) in the solution is _________Correct answer is '50 to 50'. Can you explain this answer?
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