If 20% of A = 30% of B = 1/6 of C, then find A B C.a)12 15 18b)15 ...
20% of A = 30% of B = 1/6 of C
⇒ 20/100 × A = 30/100 × B = 1/6 × C
⇒ A/5 = 3B/10 = C/6
⇒ A ∶ B ∶ C = 5 ∶ 10/3 ∶ 6 = 15 ∶ 10 ∶ 18
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If 20% of A = 30% of B = 1/6 of C, then find A B C.a)12 15 18b)15 ...
Given:
20% of A = 30% of B = 1/6 of C
To find A, B, and C, we can set up a system of equations and solve for the variables.
Let's assign variables to A, B, and C:
Let A = x
Let B = y
Let C = z
According to the given information:
20% of A = 30% of B
This can be written as:
0.2x = 0.3y
30% of B = 1/6 of C
This can be written as:
0.3y = (1/6)z
Now, we have two equations:
0.2x = 0.3y
0.3y = (1/6)z
Solving for x in terms of y:
0.2x = 0.3y
x = (0.3y) / 0.2
x = (3/2)y
Substituting this value of x in the second equation:
0.3y = (1/6)z
(3/10)y = (1/6)z
y = (10/18)z
y = (5/9)z
Now, we have three equations:
x = (3/2)y
y = (5/9)z
To simplify these equations, let's assume a common denominator of 18:
x = (27/18)y
y = (10/18)z
Simplifying further:
x = (3/2)y
y = (5/9)z
Now, we can substitute the value of y from the second equation into the first equation:
x = (3/2)(5/9)z
x = (15/18)z
x = (5/6)z
So, the values of A, B, and C are:
A = x = (5/6)z
B = y = (5/9)z
C = z
Comparing the options provided, we find that option B: 15 10 18 satisfies the given conditions:
A = (5/6)z = (5/6)(18) = 15
B = (5/9)z = (5/9)(18) = 10
C = z = 18
Therefore, the correct answer is option B: 15 10 18.