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ABCD is a cyclic trapezium with AB the diameter, AB ∥ CD, BC = 4 cm and AB = 10 cm, then find the length of side CD.
  • a)
    6.8 cm
  • b)
    6.4 cm
  • c)
    6.6 cm
  • d)
    6 cm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
ABCD is a cyclic trapezium with AB the diameter, AB CD, BC = 4 cm and...
A cyclic trapezium is an isosceles trapezium also,

cosα = x/BC = x/4      ----(1)
In ΔACB, cosα = 4/10 = 2/5      ----(2)
Equating both equations,
⇒ x/4 = 2/5
⇒ x = 1.6 cm
∴ CD = 10 – 1.6 – 1.6 = 6.8 cm
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ABCD is a cyclic trapezium with AB the diameter, AB CD, BC = 4 cm and AB = 10 cm, then find the length of side CD.a)6.8 cmb)6.4 cmc)6.6 cmd)6 cmCorrect answer is option 'A'. Can you explain this answer?
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