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If Sita walks at 5 kmph, she misses her train by 10 minutes. If she walks at 7 kmph, she reaches the station 10 minutes early. How much distance does she walk to the station?
- a)5.8 km
- b)35.6 km
- c)10.6 km
- d)92 km
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If Sita walks at 5 kmph, she misses her train by 10 minutes. If she wa...
The distance to the station can be calculated as follows:
Let's denote the distance to the station as "d" (in km), and the time difference between the two cases as "t" (in minutes).
In the first case, Sita walks at 5 km/h and misses the train by 10 minutes. So the time it would take her to get to the train on time is: d/5 (in hours) + 10/60 (in hours) = d/5 + 1/6 (in hours).
In the second case, Sita walks at 7 km/h and arrives 10 minutes early. So the time it takes her to get to the train is: d/7 - 10/60 = d/7 - 1/6 (in hours).
Since these two times should be the same, we can equate them:
d/5 + 1/6 = d/7 - 1/6
Solving this equation for "d" gives:
d = 35/6 km = 5.8 km
So the correct answer is 5.8 km.
Let's denote the distance to the station as "d" (in km), and the time difference between the two cases as "t" (in minutes).
In the first case, Sita walks at 5 km/h and misses the train by 10 minutes. So the time it would take her to get to the train on time is: d/5 (in hours) + 10/60 (in hours) = d/5 + 1/6 (in hours).
In the second case, Sita walks at 7 km/h and arrives 10 minutes early. So the time it takes her to get to the train is: d/7 - 10/60 = d/7 - 1/6 (in hours).
Since these two times should be the same, we can equate them:
d/5 + 1/6 = d/7 - 1/6
Solving this equation for "d" gives:
d = 35/6 km = 5.8 km
So the correct answer is 5.8 km.
Most Upvoted Answer
If Sita walks at 5 kmph, she misses her train by 10 minutes. If she wa...
Given data:
- Sita's speed is 5 kmph and 7 kmph for missing and reaching the train respectively.
- The time difference between both cases is 20 minutes (10 minutes late and 10 minutes early).
- We need to find the distance Sita walks to the station.
Let's assume the distance to the station as 'd' km.
Calculations:
- Let's calculate the time taken by Sita to reach the station at 5 kmph.
Let the time taken be 't1' hours.
According to the question,
d/5 = t1 + 10/60 (as she misses the train by 10 minutes)
d/5 = t1 + 1/6
- Let's calculate the time taken by Sita to reach the station at 7 kmph.
Let the time taken be 't2' hours.
According to the question,
d/7 = t2 - 10/60 (as she reaches 10 minutes early)
d/7 = t2 - 1/6
- We know that the time difference between both cases is 20 minutes.
Therefore,
t1 + 1/6 - t2 + 1/6 = 1/3 (as 20 minutes = 1/3 hours)
t1 - t2 = 1/2
- Now, let's solve the above equations to find the distance 'd'.
From equation (1), t1 = d/5 - 1/6
From equation (2), t2 = d/7 + 1/6
Substituting values of t1 and t2 in equation (3), we get:
d/5 - 1/6 - d/7 - 1/6 = 1/2
Simplifying the above equation, we get:
d = 5.8 km
Therefore, Sita walks a distance of 5.8 km to the station.
Hence, the correct answer is option (a) 5.8 km.
- Sita's speed is 5 kmph and 7 kmph for missing and reaching the train respectively.
- The time difference between both cases is 20 minutes (10 minutes late and 10 minutes early).
- We need to find the distance Sita walks to the station.
Let's assume the distance to the station as 'd' km.
Calculations:
- Let's calculate the time taken by Sita to reach the station at 5 kmph.
Let the time taken be 't1' hours.
According to the question,
d/5 = t1 + 10/60 (as she misses the train by 10 minutes)
d/5 = t1 + 1/6
- Let's calculate the time taken by Sita to reach the station at 7 kmph.
Let the time taken be 't2' hours.
According to the question,
d/7 = t2 - 10/60 (as she reaches 10 minutes early)
d/7 = t2 - 1/6
- We know that the time difference between both cases is 20 minutes.
Therefore,
t1 + 1/6 - t2 + 1/6 = 1/3 (as 20 minutes = 1/3 hours)
t1 - t2 = 1/2
- Now, let's solve the above equations to find the distance 'd'.
From equation (1), t1 = d/5 - 1/6
From equation (2), t2 = d/7 + 1/6
Substituting values of t1 and t2 in equation (3), we get:
d/5 - 1/6 - d/7 - 1/6 = 1/2
Simplifying the above equation, we get:
d = 5.8 km
Therefore, Sita walks a distance of 5.8 km to the station.
Hence, the correct answer is option (a) 5.8 km.
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If Sita walks at 5 kmph, she misses her train by 10 minutes. If she walks at 7 kmph, she reaches the station 10 minutes early. How much distance does she walk to the station?a)5.8 kmb)35.6 kmc)10.6 kmd)92 kmCorrect answer is option 'A'. Can you explain this answer?
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If Sita walks at 5 kmph, she misses her train by 10 minutes. If she walks at 7 kmph, she reaches the station 10 minutes early. How much distance does she walk to the station?a)5.8 kmb)35.6 kmc)10.6 kmd)92 kmCorrect answer is option 'A'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about If Sita walks at 5 kmph, she misses her train by 10 minutes. If she walks at 7 kmph, she reaches the station 10 minutes early. How much distance does she walk to the station?a)5.8 kmb)35.6 kmc)10.6 kmd)92 kmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If Sita walks at 5 kmph, she misses her train by 10 minutes. If she walks at 7 kmph, she reaches the station 10 minutes early. How much distance does she walk to the station?a)5.8 kmb)35.6 kmc)10.6 kmd)92 kmCorrect answer is option 'A'. Can you explain this answer?.
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