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Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.
Correct answer is '4096'. Can you explain this answer?
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Assume an instruction set that uses fixed 20 bit instruction length o...
Let x be the number of 1 operand
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Total op-codes possible =16.
Remaining op-codes for 1 operand instruction=(16-P)
Possible 1 operand instruction=(16-P)28
Remaining op codes for zero operand instruction = (16-P) x 28 - x
Possible zero operand instruction
= ((16-P)28 – x) 28 = Q
1 operand instruction is maximum when P=Q=0
((16 - 0)28 - x)28 = 0
1628 = x
x = 212 = 4096.
Most Upvoted Answer
Assume an instruction set that uses fixed 20 bit instruction length o...
Given:
- Instruction set uses fixed 20-bit instruction length
- Operands are 8-bits in length
- P two-operand instructions
- Q zero-operand instructions
To find:
- Maximum number of one-operand instructions that can be supported
Solution:
In a fixed 20-bit instruction length, we need to determine the number of bits required for each instruction type (two-operand, zero-operand, and one-operand) to calculate the maximum number of instructions that can be supported.
Determining bits required for two-operand instructions:
- Each two-operand instruction requires an opcode and two 8-bit operands.
- Since the instruction length is fixed at 20 bits, the opcode will require 20 - 8 - 8 = 4 bits.
- The remaining 8 bits are used for the two operands.
Determining bits required for zero-operand instructions:
- Each zero-operand instruction requires only an opcode.
- Since the instruction length is fixed at 20 bits, the opcode will require 20 - 8 = 12 bits.
Determining bits required for one-operand instructions:
- Each one-operand instruction requires an opcode and one 8-bit operand.
- Since the instruction length is fixed at 20 bits, the opcode will require 20 - 8 = 12 bits.
- The remaining 8 bits are used for the operand.
Calculating the maximum number of instructions:
- The maximum number of instructions for each type can be calculated using the formula 2^n, where n is the number of bits for that instruction type.
- For two-operand instructions: 2^4 = 16
- For zero-operand instructions: 2^12 = 4096
- For one-operand instructions: 2^12 = 4096
Answer:
The maximum number of one-operand instructions that can be supported is 4096.
- Instruction set uses fixed 20-bit instruction length
- Operands are 8-bits in length
- P two-operand instructions
- Q zero-operand instructions
To find:
- Maximum number of one-operand instructions that can be supported
Solution:
In a fixed 20-bit instruction length, we need to determine the number of bits required for each instruction type (two-operand, zero-operand, and one-operand) to calculate the maximum number of instructions that can be supported.
Determining bits required for two-operand instructions:
- Each two-operand instruction requires an opcode and two 8-bit operands.
- Since the instruction length is fixed at 20 bits, the opcode will require 20 - 8 - 8 = 4 bits.
- The remaining 8 bits are used for the two operands.
Determining bits required for zero-operand instructions:
- Each zero-operand instruction requires only an opcode.
- Since the instruction length is fixed at 20 bits, the opcode will require 20 - 8 = 12 bits.
Determining bits required for one-operand instructions:
- Each one-operand instruction requires an opcode and one 8-bit operand.
- Since the instruction length is fixed at 20 bits, the opcode will require 20 - 8 = 12 bits.
- The remaining 8 bits are used for the operand.
Calculating the maximum number of instructions:
- The maximum number of instructions for each type can be calculated using the formula 2^n, where n is the number of bits for that instruction type.
- For two-operand instructions: 2^4 = 16
- For zero-operand instructions: 2^12 = 4096
- For one-operand instructions: 2^12 = 4096
Answer:
The maximum number of one-operand instructions that can be supported is 4096.
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Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer?
Question Description
Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer?.
Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assume an instruction set that uses fixed 20 bit instruction length operands are 8 bits in length. There are P two operand instructions and Q zero operand instructions. Find the maximum number of one operand instruction that can be supported.Correct answer is '4096'. Can you explain this answer?.
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