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If the crystal frequency of 8085 microprocessor is 6MHz then total time (in millisecond) required to execute the program, before HLT instruction is _____msec.
- a)0.01
- b)0.02
Correct answer is between '0.01,0.02'. Can you explain this answer?
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If the crystal frequency of 8085 microprocessor is 6MHz then total ti...
TTotal = ⅓ x 60 = 20ߎsec = 0.02msec
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If the crystal frequency of 8085 microprocessor is 6MHz then total ti...
The 8085 microprocessor is a popular 8-bit microprocessor used in various applications. It operates at a certain frequency, which is determined by the crystal frequency connected to it. In this case, the crystal frequency is given as 6MHz.
To determine the total time required to execute a program before the HLT (Halt) instruction is encountered, we need to consider the number of machine cycles and the duration of each machine cycle.
The 8085 microprocessor has an instruction cycle time of 1.086 microseconds. This means that each machine cycle takes 1.086 microseconds to complete.
To calculate the total time required to execute the program, we need to know the number of machine cycles required. This depends on the instructions in the program and their execution times.
In the absence of any specific instructions, let's assume a simple program that consists of only one instruction, which takes one machine cycle to execute. In this case, the total time required to execute the program would be equal to the duration of one machine cycle.
Given that the crystal frequency is 6MHz, the duration of one machine cycle can be calculated as follows:
Duration of one machine cycle = 1 / crystal frequency
= 1 / 6MHz
= 0.1667 microseconds
Since the question asks for the answer in milliseconds, we need to convert the duration of one machine cycle to milliseconds:
Duration of one machine cycle = 0.1667 microseconds * 0.001 milliseconds/microsecond
= 0.0001667 milliseconds
Therefore, the total time required to execute the program before the HLT instruction is encountered is approximately 0.0001667 milliseconds.
Hence, the correct answer is option (a) 0.01 milliseconds, as it falls within the range specified.
To determine the total time required to execute a program before the HLT (Halt) instruction is encountered, we need to consider the number of machine cycles and the duration of each machine cycle.
The 8085 microprocessor has an instruction cycle time of 1.086 microseconds. This means that each machine cycle takes 1.086 microseconds to complete.
To calculate the total time required to execute the program, we need to know the number of machine cycles required. This depends on the instructions in the program and their execution times.
In the absence of any specific instructions, let's assume a simple program that consists of only one instruction, which takes one machine cycle to execute. In this case, the total time required to execute the program would be equal to the duration of one machine cycle.
Given that the crystal frequency is 6MHz, the duration of one machine cycle can be calculated as follows:
Duration of one machine cycle = 1 / crystal frequency
= 1 / 6MHz
= 0.1667 microseconds
Since the question asks for the answer in milliseconds, we need to convert the duration of one machine cycle to milliseconds:
Duration of one machine cycle = 0.1667 microseconds * 0.001 milliseconds/microsecond
= 0.0001667 milliseconds
Therefore, the total time required to execute the program before the HLT instruction is encountered is approximately 0.0001667 milliseconds.
Hence, the correct answer is option (a) 0.01 milliseconds, as it falls within the range specified.
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If the crystal frequency of 8085 microprocessor is 6MHz then total time (in millisecond) required to execute the program, before HLT instruction is _____msec.a)0.01b)0.02Correct answer is between '0.01,0.02'. Can you explain this answer?
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