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If 53g Na2CO3 is dissolved in 500 ml solution. Find the Molarity of Na ion & (CO3) ²- ion Can anyone explain this?
Most Upvoted Answer
If 53g Na2CO3 is dissolved in 500 ml solution. Find the Molarity of Na...
First, we need to calculate the number of moles of Na2CO3 present in the solution:

Moles of Na2CO3 = Mass / Molar mass
= 53g / (2 x 23g/mol + 12g/mol + 3 x 16g/mol)
= 0.5 moles

Next, we need to calculate the number of moles of Na+ ions present in the solution. Each molecule of Na2CO3 contains 2 Na+ ions, so the total number of moles of Na+ ions is:

Moles of Na+ = 2 x Moles of Na2CO3
= 2 x 0.5 moles
= 1 mole

Finally, we can calculate the molarity of Na+ ions by dividing the number of moles by the volume of the solution in liters:

Molarity of Na+ = Moles of Na+ / Volume of solution in liters
= 1 mole / 0.5 liters
= 2 M

Therefore, the molarity of Na+ ion is 2 M.
Community Answer
If 53g Na2CO3 is dissolved in 500 ml solution. Find the Molarity of Na...
Solute=53g
mole of solute=53/106
=0.5 mol
solution in liter=500/1000=0.5
Na ion present in solution is =2
(CO3)- ion present in solution=1
Then,
Molarity=no.of mole of ion/volume of solution in liter
1.molarity of Na ion
M=2/0.5
M=4
2.molarity of CO3 ion
M=1/0.5
M=2
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If 53g Na2CO3 is dissolved in 500 ml solution. Find the Molarity of Na ion & (CO3) ²- ion Can anyone explain this?
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