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A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.
The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.
- a)39.5
- b)4.05
Correct answer is between '39.5,4.05'. Can you explain this answer?
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Verified Answer
A 200 V, unsaturated shunt motor has an armature resistance (includin...
As, armature current is nearly equal to supply current. The value of back emf will not change much
As we known,
is nearly constant
Renva = 240 - 200 = 40Ω
Most Upvoted Answer
A 200 V, unsaturated shunt motor has an armature resistance (includin...
Given data:
- Supply voltage (V) = 200 V
- Armature resistance (Ra) = 0.05 Ω
- Field resistance (Rf) = 200 Ω
- Initial speed (N1) = 1500 RPM
- Final speed (N2) = 1800 RPM
- Supply current (I) = 300 A
Calculating the armature current:
The armature current (Ia) can be calculated using Ohm's law:
Ia = V / Ra
= 200 / 0.05
= 4000 A
Calculating the initial back EMF:
The back EMF (Eb1) can be calculated using the formula:
Eb1 = V - Ia * Ra
= 200 - 4000 * 0.05
= 200 - 200
= 0 V
Calculating the initial field current:
The field current (If1) can be calculated using Ohm's law:
If1 = V / Rf
= 200 / 200
= 1 A
Calculating the initial torque:
The initial torque (T1) can be calculated using the formula:
T1 = (Eb1 * Ia) / N1
= (0 * 4000) / 1500
= 0 Nm
Calculating the final back EMF:
The final back EMF (Eb2) can be calculated using the formula:
Eb2 = V - Ia * Ra
= 200 - 4000 * 0.05
= 200 - 200
= 0 V
Calculating the final field current:
The final field current (If2) can be calculated using Ohm's law:
If2 = V / Rf2
= 200 / Rf2
Calculating the final torque:
The final torque (T2) can be calculated using the formula:
T2 = (Eb2 * Ia) / N2
= (0 * 4000) / 1800
= 0 Nm
Calculating the change in torque:
The change in torque (ΔT) can be calculated using the formula:
ΔT = T2 - T1
= 0 - 0
= 0 Nm
Calculating the change in field current:
The change in field current (ΔIf) can be calculated using the formula:
ΔIf = If2 - If1
= V / Rf2 - V / Rf
= V (1 / Rf2 - 1 / Rf)
= 200 (1 / Rf2 - 1 / 200)
Calculating the resistance to be added in the field circuit:
To increase the speed from 1500 RPM to 1800 RPM, the change in field current (ΔIf) should be 300 A. So, we can equate ΔIf to 300 A and solve for Rf2:
300 = 200 (1 / Rf2 - 1 / 200)
1
- Supply voltage (V) = 200 V
- Armature resistance (Ra) = 0.05 Ω
- Field resistance (Rf) = 200 Ω
- Initial speed (N1) = 1500 RPM
- Final speed (N2) = 1800 RPM
- Supply current (I) = 300 A
Calculating the armature current:
The armature current (Ia) can be calculated using Ohm's law:
Ia = V / Ra
= 200 / 0.05
= 4000 A
Calculating the initial back EMF:
The back EMF (Eb1) can be calculated using the formula:
Eb1 = V - Ia * Ra
= 200 - 4000 * 0.05
= 200 - 200
= 0 V
Calculating the initial field current:
The field current (If1) can be calculated using Ohm's law:
If1 = V / Rf
= 200 / 200
= 1 A
Calculating the initial torque:
The initial torque (T1) can be calculated using the formula:
T1 = (Eb1 * Ia) / N1
= (0 * 4000) / 1500
= 0 Nm
Calculating the final back EMF:
The final back EMF (Eb2) can be calculated using the formula:
Eb2 = V - Ia * Ra
= 200 - 4000 * 0.05
= 200 - 200
= 0 V
Calculating the final field current:
The final field current (If2) can be calculated using Ohm's law:
If2 = V / Rf2
= 200 / Rf2
Calculating the final torque:
The final torque (T2) can be calculated using the formula:
T2 = (Eb2 * Ia) / N2
= (0 * 4000) / 1800
= 0 Nm
Calculating the change in torque:
The change in torque (ΔT) can be calculated using the formula:
ΔT = T2 - T1
= 0 - 0
= 0 Nm
Calculating the change in field current:
The change in field current (ΔIf) can be calculated using the formula:
ΔIf = If2 - If1
= V / Rf2 - V / Rf
= V (1 / Rf2 - 1 / Rf)
= 200 (1 / Rf2 - 1 / 200)
Calculating the resistance to be added in the field circuit:
To increase the speed from 1500 RPM to 1800 RPM, the change in field current (ΔIf) should be 300 A. So, we can equate ΔIf to 300 A and solve for Rf2:
300 = 200 (1 / Rf2 - 1 / 200)
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A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer?
Question Description
A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer?.
A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer?.
Solutions for A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer?, a detailed solution for A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? has been provided alongside types of A 200 V, unsaturated shunt motor has an armature resistance (including brushes and interpolar winding) of 0.05 Ω and field resistance of 200 Ω.The value of resistance in Ω to be added in the field circuits increases the speed from 1500 RPM to 1800 RPM. When the supply current is 300 A.a)39.5b)4.05Correct answer is between '39.5,4.05'. Can you explain this answer? theory, EduRev gives you an
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