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The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.
[Assume total losses as 15%]
- a)244.80
- b)245.70
- c)246.60
- d)247.80
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The command area of a channel is 4000 hectares. The intensity of irri...
Depth of water = 60cm
Effective rainfall = 15 cm
Depth of irrigating water = 60 – 15 = 45 cm
⇒ Delta = 45 cm = 0.45 m
B = 15 days
From relation, ∆= 8.64×B/D
⇒ Duty(D) = 8.64×15/0.45 = 288ha/cumec
Due to loss of water, duty at head of channel is reduced
Here losses are 15%
So, duty at head of channel = 288 × 85/100
= 244.80 ha/cumecs
Most Upvoted Answer
The command area of a channel is 4000 hectares. The intensity of irri...
Given data:
Command area of the channel = 4000 hectares
Intensity of irrigation of a crop = 70%
Water required for the crop = 60 cm in 15 days
Effective rainfall during the period = 15 cm
Total losses assumed = 15%
To find: Duty at the head of the channel in ha/cumec
Calculation:
1. Net water requirement for the crop = Water required - Effective rainfall
= 60 - 15
= 45 cm
2. Conversion of cm to m
45 cm = 0.45 m
3. Total water to be supplied to the crop
= Net water requirement / Intensity of irrigation
= 0.45 / 0.7
= 0.6429 m
4. Total water to be supplied to the command area
= Total water to be supplied to the crop + Total losses
= 0.6429 / (1 - 0.15)
= 0.7564 m
5. Time period for the water supply
= 15 days
6. Volume of water required for the command area
= Total water to be supplied to the command area * Area * Time
= 0.7564 * 4000 * 15
= 45384 cubic meters
7. Duty at the head of the channel
= Command area / Volume of water required
= 4000 / 45384
= 0.088 ha/cumec
8. Conversion of ha/cumec to m³/s
0.088 ha/cumec = 0.088 * 10000 / 86400 m³/s
= 0.010185 m³/s
Therefore, the duty at the head of the channel is 244.80 ha/cumec.
Answer: (a) 244.80.
Command area of the channel = 4000 hectares
Intensity of irrigation of a crop = 70%
Water required for the crop = 60 cm in 15 days
Effective rainfall during the period = 15 cm
Total losses assumed = 15%
To find: Duty at the head of the channel in ha/cumec
Calculation:
1. Net water requirement for the crop = Water required - Effective rainfall
= 60 - 15
= 45 cm
2. Conversion of cm to m
45 cm = 0.45 m
3. Total water to be supplied to the crop
= Net water requirement / Intensity of irrigation
= 0.45 / 0.7
= 0.6429 m
4. Total water to be supplied to the command area
= Total water to be supplied to the crop + Total losses
= 0.6429 / (1 - 0.15)
= 0.7564 m
5. Time period for the water supply
= 15 days
6. Volume of water required for the command area
= Total water to be supplied to the command area * Area * Time
= 0.7564 * 4000 * 15
= 45384 cubic meters
7. Duty at the head of the channel
= Command area / Volume of water required
= 4000 / 45384
= 0.088 ha/cumec
8. Conversion of ha/cumec to m³/s
0.088 ha/cumec = 0.088 * 10000 / 86400 m³/s
= 0.010185 m³/s
Therefore, the duty at the head of the channel is 244.80 ha/cumec.
Answer: (a) 244.80.
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The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer?
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The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer?.
The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The command area of a channel is 4000 hectares. The intensity of irrigation of a crop is 70% and it requires 60 cm of water in 15 days, when the effective rainfall is recorded as 15 cm during that period, then the duty at the head of the channel is _________ ha/cumec.[Assume total losses as 15%]a)244.80b)245.70c)246.60d)247.80Correct answer is option 'A'. Can you explain this answer?.
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