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Consider a processor that includes a base register with indexing addressing mode. Suppose an instruction is encountered that employs this addressing mode and specifies a displacement of 7B2, in hexadecimal. Currently the base and index register contain the decimal numbers 48022 and 8, respectively. What is the address of the operand (In Decimal)?
  • a)
    50000
  • b)
    48030
  • c)
    49992
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Consider a processor that includes a base register with indexing addr...
Address of operand= base register value + Index Value + Displacement
= 48022 + 8+ 1970
= 50000
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Most Upvoted Answer
Consider a processor that includes a base register with indexing addr...
Given Information:
- Base register contains decimal number 48022
- Index register contains decimal number 8
- Displacement is 7B2 in hexadecimal

To find:
The address of the operand in decimal.

Solution:
First, let's convert the displacement from hexadecimal to decimal.

In hexadecimal, B represents 11. So, 7B2 can be expanded as:
7 x 16^2 + 11 x 16^1 + 2 x 16^0 = 1792 + 176 + 2 = 1970

Calculating the address:
To calculate the address, we need to add the base register value, index register value, and displacement.

Address = Base + Index + Displacement

Substituting the given values:
Address = 48022 + 8 + 1970 = 50000

Therefore, the address of the operand is 50000 in decimal.

Answer:
The address of the operand is option A) 50000.
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Consider a processor that includes a base register with indexing addressing mode. Suppose an instruction is encountered that employs this addressing mode and specifies a displacement of 7B2, in hexadecimal. Currently the base and index register contain the decimal numbers 48022 and 8, respectively. What is the address of the operand (In Decimal)?a)50000b)48030c)49992d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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