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The areas of ram and plunger of a hydraulic press are 40mm2 and 2 mm2 respectively. The plunger applies a force of 500N, determine the weight lifted based on the intensity of pressure measured at ram.
- a)0.5 kN
- b)5 kN
- c)10 kN
- d)2.43 kN
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
The areas of ram and plunger of a hydraulic press are 40mm2 and 2 mm2...
Given: AR = 0.04 m2, AP = 0.002m2
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F = 500N
Intensity of pressure due to plunger,
P = F/AP = 500 / 0.002
P = 2.5 × 105 N/m2
Since the intensity of pressure will be equally transmitted, therefore intensity of pressure at ram will be same. (by Pascal’s law)
Intensity of pressure at ram = W / AR
2.5 × 105 = W / 0.04
W = 10 kN
Most Upvoted Answer
The areas of ram and plunger of a hydraulic press are 40mm2 and 2 mm2...
Calculation:
Step 1: Calculate the pressure at the ram
Given:
Area of ram (A1) = 40 mm^2 = 40 x 10^-6 m^2
Force applied by the plunger (F) = 500 N
Pressure (P) = Force/Area = F/A1 = 500 N / 40 x 10^-6 m^2
P = 12,500,000 Pa = 12.5 MPa
Step 2: Calculate the force at the ram
Given:
Area of plunger (A2) = 2 mm^2 = 2 x 10^-6 m^2
Using the formula:
F = P x A2
F = 12.5 MPa x 2 x 10^-6 m^2
F = 0.025 N
Therefore, the weight lifted based on the intensity of pressure measured at the ram is 0.025 kN, which is option C.
Step 1: Calculate the pressure at the ram
Given:
Area of ram (A1) = 40 mm^2 = 40 x 10^-6 m^2
Force applied by the plunger (F) = 500 N
Pressure (P) = Force/Area = F/A1 = 500 N / 40 x 10^-6 m^2
P = 12,500,000 Pa = 12.5 MPa
Step 2: Calculate the force at the ram
Given:
Area of plunger (A2) = 2 mm^2 = 2 x 10^-6 m^2
Using the formula:
F = P x A2
F = 12.5 MPa x 2 x 10^-6 m^2
F = 0.025 N
Therefore, the weight lifted based on the intensity of pressure measured at the ram is 0.025 kN, which is option C.
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