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A Cipolletti weir discharges water with the head of water over the crest being 20 cm. If the head due to velocity of approach is 0.02 m, what will be the excess percentage of flow, when corrected for velocity of approach as compared to when not corrected?
  • a)
    12.1
  • b)
    12.5
Correct answer is between '12.1,12.5'. Can you explain this answer?
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A Cipolletti weir discharges water with the head of water over the cr...
When velocity of approach is taken into consideration,
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A Cipolletti weir discharges water with the head of water over the cr...
Given:
- Head over the crest due to velocity of approach (ha) = 0.02 m
- Head over the crest without velocity of approach (h) = 20 cm = 0.2 m

To find:
Excess percentage of flow when corrected for velocity of approach as compared to when not corrected

Solution:
The excess percentage of flow can be calculated using the formula:

Excess Percentage = [(ha - h) / h] × 100

Let's substitute the given values into the formula to calculate the excess percentage:

Excess Percentage = [(0.02 - 0.2) / 0.2] × 100
= [-0.18 / 0.2] × 100
= -0.9 × 100
= -90%

The negative sign indicates that the flow is reduced when corrected for velocity of approach.

Correcting the Flow:
When water approaches a weir with a velocity, the actual head over the crest is reduced due to the kinetic energy of the approaching water. This reduction in head is known as the head due to velocity of approach.

To correct for the velocity of approach, the actual head is given by:

h' = h + ha

where h' is the corrected head.

In this case, h' = 0.2 m + 0.02 m
= 0.22 m

Calculating the Excess Percentage:
Now, let's calculate the excess percentage of flow when corrected for velocity of approach:

Excess Percentage = [(ha - h') / h'] × 100

Excess Percentage = [(0.02 - 0.22) / 0.22] × 100
= [-0.2 / 0.22] × 100
≈ -0.909 × 100
≈ -90.9%

The negative sign indicates that the flow is still reduced when corrected for velocity of approach.

Conclusion:
The excess percentage of flow, when corrected for velocity of approach as compared to when not corrected, is approximately -90.9%. Since the correct answer is between 12.1 and 12.5, it seems there may be an error in the calculation or in the given options.
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A Cipolletti weir discharges water with the head of water over the crest being 20 cm. If the head due to velocity of approach is 0.02 m, what will be the excess percentage of flow, when corrected for velocity of approach as compared to when not corrected?a)12.1b)12.5Correct answer is between '12.1,12.5'. Can you explain this answer?
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