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Biotransformation of an organic compound having concentration (x) can be modeted using an ordinary differential equation where k is the reaction rate constant, If x = a at t = 0, the solution of the equation is
  • a)
    x = ae - kt
  • b)
  • c)
    x = a ( l - e - kt)
  • d)
    x - a + kt
Correct answer is option 'B'. Can you explain this answer?
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Biotransformation of an organic compound having concentration (x) can...
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Biotransformation of an organic compound having concentration (x) can be modeted using an ordinary differential equation where k is the reaction rate constant, If x = a at t = 0, the solution of the equation isa)x = ae - ktb)c)x = a ( l - e - kt)d)x - a + ktCorrect answer is option 'B'. Can you explain this answer?
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Biotransformation of an organic compound having concentration (x) can be modeted using an ordinary differential equation where k is the reaction rate constant, If x = a at t = 0, the solution of the equation isa)x = ae - ktb)c)x = a ( l - e - kt)d)x - a + ktCorrect answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Biotransformation of an organic compound having concentration (x) can be modeted using an ordinary differential equation where k is the reaction rate constant, If x = a at t = 0, the solution of the equation isa)x = ae - ktb)c)x = a ( l - e - kt)d)x - a + ktCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Biotransformation of an organic compound having concentration (x) can be modeted using an ordinary differential equation where k is the reaction rate constant, If x = a at t = 0, the solution of the equation isa)x = ae - ktb)c)x = a ( l - e - kt)d)x - a + ktCorrect answer is option 'B'. Can you explain this answer?.
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