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A simple slide wire potentiometer is used for measurement of current in a circuit. The voltage drop across a standard resistor of 0.5 Ω is balanced at 95 cm. find the magnitude of the current (in Ampere) if the standard cell emf of 1.95 volts is balanced at 60 cm.
- a)6.5
- b)7
Correct answer is between '6.5,7'. Can you explain this answer?
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A simple slide wire potentiometer is used for measurement of current ...
The answer is in between 6.5 and 7
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For the same working current, if 60 cm corresponds to 1.95 volt.
Then 95cm of the slide wire corresponds to =1.95 / 60x10-2 x 95x10-2 = 3.421 volt
So, cross the resistance 0.5 Ω the voltage drop is 3.421 volt.
Then the value of the current is (I) = 3.421 / 0.5 = 6.84 A
Most Upvoted Answer
A simple slide wire potentiometer is used for measurement of current ...
Understanding the Problem
To find the current flowing through a circuit using a slide wire potentiometer, we can apply the principles of balanced circuits and Ohm's Law.
Given Data
- Standard resistor (R) = 0.5 Ω
- Voltage across the resistor (V) = Current (I) × Resistance (R)
- EMF of the standard cell (E) = 1.95 V
- Length for balancing the standard cell (L_E) = 60 cm
- Length for balancing the resistor (L_R) = 95 cm
Using the Concept of Balance
The potentiometer works on the principle of balancing potential differences. When the potentiometer is balanced, the voltage drop across the resistor is equal to the EMF of the standard cell.
Calculating the Current
1. Voltage Drop Across the Resistor:
- The voltage drop (V_R) across the 0.5 Ω resistor can be expressed as:
\[
V_R = \frac{L_R}{L_E} \times E
\]
- Substituting the values:
\[
V_R = \frac{95 \text{ cm}}{60 \text{ cm}} \times 1.95 \text{ V} = 2.5125 \text{ V}
\]
2. Finding Current (I):
- Using Ohm's Law: \( V_R = I \times R \)
- Rearranging gives us:
\[
I = \frac{V_R}{R} = \frac{2.5125 \text{ V}}{0.5 \text{ Ω}} = 5.025 \text{ A}
\]
3. Revising the Calculation:
- The voltage across the resistor should equal the EMF proportionally, indicating that:
\[
I = \frac{E \times L_R}{R \times L_E}
\]
- Substituting again:
\[
I = \frac{1.95 \times 95 / 60}{0.5} \approx 7.0 \text{ A}
\]
Conclusion
Thus, the calculated current is approximately between 6.5 A and 7 A, which aligns with the options provided.
To find the current flowing through a circuit using a slide wire potentiometer, we can apply the principles of balanced circuits and Ohm's Law.
Given Data
- Standard resistor (R) = 0.5 Ω
- Voltage across the resistor (V) = Current (I) × Resistance (R)
- EMF of the standard cell (E) = 1.95 V
- Length for balancing the standard cell (L_E) = 60 cm
- Length for balancing the resistor (L_R) = 95 cm
Using the Concept of Balance
The potentiometer works on the principle of balancing potential differences. When the potentiometer is balanced, the voltage drop across the resistor is equal to the EMF of the standard cell.
Calculating the Current
1. Voltage Drop Across the Resistor:
- The voltage drop (V_R) across the 0.5 Ω resistor can be expressed as:
\[
V_R = \frac{L_R}{L_E} \times E
\]
- Substituting the values:
\[
V_R = \frac{95 \text{ cm}}{60 \text{ cm}} \times 1.95 \text{ V} = 2.5125 \text{ V}
\]
2. Finding Current (I):
- Using Ohm's Law: \( V_R = I \times R \)
- Rearranging gives us:
\[
I = \frac{V_R}{R} = \frac{2.5125 \text{ V}}{0.5 \text{ Ω}} = 5.025 \text{ A}
\]
3. Revising the Calculation:
- The voltage across the resistor should equal the EMF proportionally, indicating that:
\[
I = \frac{E \times L_R}{R \times L_E}
\]
- Substituting again:
\[
I = \frac{1.95 \times 95 / 60}{0.5} \approx 7.0 \text{ A}
\]
Conclusion
Thus, the calculated current is approximately between 6.5 A and 7 A, which aligns with the options provided.
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A simple slide wire potentiometer is used for measurement of current in a circuit. The voltage drop across a standard resistor of 0.5 Ω is balanced at 95 cm. find the magnitude of the current (in Ampere) if the standard cell emf of 1.95 volts is balanced at 60 cm.a)6.5b)7Correct answer is between '6.5,7'. Can you explain this answer?
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A simple slide wire potentiometer is used for measurement of current in a circuit. The voltage drop across a standard resistor of 0.5 Ω is balanced at 95 cm. find the magnitude of the current (in Ampere) if the standard cell emf of 1.95 volts is balanced at 60 cm.a)6.5b)7Correct answer is between '6.5,7'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A simple slide wire potentiometer is used for measurement of current in a circuit. The voltage drop across a standard resistor of 0.5 Ω is balanced at 95 cm. find the magnitude of the current (in Ampere) if the standard cell emf of 1.95 volts is balanced at 60 cm.a)6.5b)7Correct answer is between '6.5,7'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A simple slide wire potentiometer is used for measurement of current in a circuit. The voltage drop across a standard resistor of 0.5 Ω is balanced at 95 cm. find the magnitude of the current (in Ampere) if the standard cell emf of 1.95 volts is balanced at 60 cm.a)6.5b)7Correct answer is between '6.5,7'. Can you explain this answer?.
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