A two generator system supplying a load of 40MW connected at bus 2. The fuel costs of generators are:C1(PG1) = 8500 Rs/MWhC2(PG2) = 11000 Rs/MWhThe loss in the line is Ploss(p.u.)=0.5PG1(p.u.)2 where the loss coefficient is specified in p.u. on a 100 MVA base. The most economic power generation schedule (in MW) is:a)PG1 = 15.9 MVA, PG2 = 13.2 MVAb)PG1 = 19.9 MVA, PG2 = 22.7 MVAc)PG1 = 13.2 MVA, PG2 = 15.9 MVAd)PG1 = 22.7 MVA, PG2 = 19.9 MVACorrect answer is option 'D'. Can you explain this answer?

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A two generator system supplying a load of 40MW connected at bus 2. The fuel costs of generators are:

C₁(P_G1) = 8500 Rs/MWh

C₂(P_G2) = 11000 Rs/MWh

The loss in the line is P_loss(p.u.)=0.5PG1_(p.u.)2 where the loss coefficient is specified in p.u. on a 100 MVA base. The most economic power generation schedule (in MW) is:

a)
P_G1 = 15.9 MVA, P_G2 = 13.2 MVA
b)
P_G1 = 19.9 MVA, P_G2 = 22.7 MVA
c)
P_G1 = 13.2 MVA, P_G2 = 15.9 MVA
d)
P_G1 = 22.7 MVA, P_G2 = 19.9 MVA

Correct answer is option 'D'. Can you explain this answer?

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A two generator system supplying a load of 40MW connected at bus 2. T...

From coordination equation,

(dF_n/dP_Gn){1/ (1-∂P_L/∂P_Gn)} =λ

Given,

P_L=0.5P_G12

∂P_L/∂P_G1=P_G1 and ∂P_L/∂P_G2=0

(dF₁/dP_G1)(1/ (1-P_G1) = (dF₂/dP_G2) (1/ (1-0)

Or, 8500(1/ (1-P_G1) = 11000

Or, PG1=0.227 p.u.

As the base value is 100MVA.

PG1=100x0.227 = 22.7MVA

PL= 0.5x(0.227)² = 0.0258 p.u. = 0.0258x100 MVA = 2.58MVA

PD=P_G1+ P_G2- PL

Or, 40=22.7+ P_G2-2.58

Or, P_G2=19.9 MVA

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A two generator system supplying a load of 40MW connected at bus 2. The fuel costs of generators are:C1(PG1) = 8500 Rs/MWhC2(PG2) = 11000 Rs/MWhThe loss in the line is Ploss(p.u.)=0.5PG1(p.u.)2 where the loss coefficient is specified in p.u. on a 100 MVA base. The most economic power generation schedule (in MW) is:a)PG1 = 15.9 MVA, PG2 = 13.2 MVAb)PG1 = 19.9 MVA, PG2 = 22.7 MVAc)PG1 = 13.2 MVA, PG2 = 15.9 MVAd)PG1 = 22.7 MVA, PG2 = 19.9 MVACorrect answer is option 'D'. Can you explain this answer?

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A two generator system supplying a load of 40MW connected at bus 2. The fuel costs of generators are:C1(PG1) = 8500 Rs/MWhC2(PG2) = 11000 Rs/MWhThe loss in the line is Ploss(p.u.)=0.5PG1(p.u.)2 where the loss coefficient is specified in p.u. on a 100 MVA base. The most economic power generation schedule (in MW) is:a)PG1 = 15.9 MVA, PG2 = 13.2 MVAb)PG1 = 19.9 MVA, PG2 = 22.7 MVAc)PG1 = 13.2 MVA, PG2 = 15.9 MVAd)PG1 = 22.7 MVA, PG2 = 19.9 MVACorrect answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A two generator system supplying a load of 40MW connected at bus 2. The fuel costs of generators are:C1(PG1) = 8500 Rs/MWhC2(PG2) = 11000 Rs/MWhThe loss in the line is Ploss(p.u.)=0.5PG1(p.u.)2 where the loss coefficient is specified in p.u. on a 100 MVA base. The most economic power generation schedule (in MW) is:a)PG1 = 15.9 MVA, PG2 = 13.2 MVAb)PG1 = 19.9 MVA, PG2 = 22.7 MVAc)PG1 = 13.2 MVA, PG2 = 15.9 MVAd)PG1 = 22.7 MVA, PG2 = 19.9 MVACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A two generator system supplying a load of 40MW connected at bus 2. The fuel costs of generators are:C1(PG1) = 8500 Rs/MWhC2(PG2) = 11000 Rs/MWhThe loss in the line is Ploss(p.u.)=0.5PG1(p.u.)2 where the loss coefficient is specified in p.u. on a 100 MVA base. The most economic power generation schedule (in MW) is:a)PG1 = 15.9 MVA, PG2 = 13.2 MVAb)PG1 = 19.9 MVA, PG2 = 22.7 MVAc)PG1 = 13.2 MVA, PG2 = 15.9 MVAd)PG1 = 22.7 MVA, PG2 = 19.9 MVACorrect answer is option 'D'. Can you explain this answer?.

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