Present average age of Kanika and Shweta is ‘x’ years. Ratio of the a...
Present age of Kanika = 16 years
Age of Kanika one year ago =16-1=15 years
Age of Monika after four years = 15×2=30 years
Present age of Monika = 30-4=26 years=26 years
e present ages of Kanika, Monika and Shweta =22×3=66 years
Present age of Shweta =66-16-26-24 years
Present average age of Kanika and Shweta =x=(24 + 16)/2=20 years
So, the value of ‘x’ is 20 years
So option (d) is the correct answer.
View all questions of this test
Present average age of Kanika and Shweta is ‘x’ years. Ratio of the a...
Given information:
- The present average age of Kanika and Shweta is 'x' years.
- The ratio of the age of Kanika one year ago to the age of Monika four years hence will be 1:2.
- The present average age of Kanika, Monika, and Shweta is 22 years.
- The present age of Kanika is 16 years.
To find: The value of 'x'.
Let's solve the problem step by step:
Step 1: Find the age of Kanika one year ago.
Since the present age of Kanika is 16 years, her age one year ago would be 16 - 1 = 15 years.
Step 2: Find the age of Monika four years hence.
Let the age of Monika four years hence be y years.
According to the given ratio,
(15 / y) = 1 / 2
Cross-multiplying,
2 * 15 = y
y = 30
Step 3: Find the sum of the present ages of Kanika, Monika, and Shweta.
The present average age of Kanika, Monika, and Shweta is 22 years.
Therefore, the sum of their present ages is 22 * 3 = 66 years.
Step 4: Find the present age of Shweta.
Since the sum of the present ages of Kanika, Monika, and Shweta is 66 years, and the present age of Kanika is 16 years, we can calculate the present age of Shweta as follows:
16 + Shweta's age = 66
Shweta's age = 66 - 16
Shweta's age = 50 years
Step 5: Find the present average age of Kanika and Shweta.
The present average age of Kanika and Shweta is 'x' years.
Therefore, (16 + 50) / 2 = x
66 / 2 = x
x = 33
Hence, the value of 'x' is 33.
Therefore, the correct answer is option 'D' (20 years)